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katovenus [111]
2 years ago
10

A car moves around a circular track at a constant rate. What must change?

Chemistry
2 answers:
lbvjy [14]2 years ago
8 0

A car moves around a circular track at a constant rate it's velocity changes.

Option-B.

<u>Explanation:</u>

As the car is moving in the circular motion, its velocity changes, as its speed is scalar and which means it is constant, velocity changes (being a vector quantity).

Its angular velocity is the speed in the direction of the curve the vehicle moves, which means it is constant, but is acted upon by an acceleration toward its center called centripetal acceleration and it is necessary to maintain the circular motion of the car.

Sergeeva-Olga [200]2 years ago
7 0

Answer:C) both its speed and its velocity.

Explanation:

changing one but not the other would cause a spin out and crash

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How many grams of fluorine are needed to generate 7.65 moles Carbon Tetrafluoride
Delicious77 [7]

Answer:

36.3375 g

Explanation:

7 0
2 years ago
Can anyone please help me
mixas84 [53]
Q1. Chemical, Physical, Physical, Physical
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4 0
3 years ago
Which equation represents a neutralization reaction?
bulgar [2K]

Answer: Hello, there! your Answer is Below

The answer is letter C

Explanation:

A. 4Fe(s) + 3O2(g) → 2Fe2O3(s), 2H2(g) + O2(g) → 2H2O() and AgNO3(aq) + KCl(aq) → KNO3(aq) + AgCl(s) are not neutralization reaction.

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4 0
3 years ago
Read 2 more answers
Data was collected by students in an acid base titration lab. They used 1.63 M Ca(OH)2(AQ)
jenyasd209 [6]

Answer:

3.8 M

Explanation:

Volume of acid used VA= 57.0 - 37.5 = 19.5 ml

Volume of base used VB= 67.8 - 45.0 = 22.8 ml

Equation of the reaction

2HNO3(aq) + Ca(OH)2(aq) --------> Ca(NO3)2(aq) + 2H2O(l)

Number of moles of acid NA= 2

Number of moles of base NB= 1

Concentration of acid CA= ???

Concentration of base CB= 1.63 M

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CA= CBVBNA/VANB

CA= 1.63 × 22.8 × 2/ 19.5 × 1

CA= 3.8 M

HENCE THE MOLARITY OF THE ACID IS 3.8 M.

6 0
2 years ago
In the United States, barometric pressures a re generally reported in inches of mercury (in. Hg). On a beautiful summer day in C
Svetllana [295]

Answer:

773.43 torr

Explanation:

From the question given above, the following data were obtained:

Pressure (in inHg) = 30.45 inHg

Pressure (in torr) =?

We can convert 30.45 inHg to torr by doing the following:

1 inHg = 25.4 torr

Therefore,

30.45 inHg = 30.45 inHg × 25.4 torr / 1 inHg

30.45 inhg = 773.43 torr

Thus, 30.45 inhg is equivalent to 773.43 torr

7 0
2 years ago
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