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katovenus [111]
3 years ago
10

A car moves around a circular track at a constant rate. What must change?

Chemistry
2 answers:
lbvjy [14]3 years ago
8 0

A car moves around a circular track at a constant rate it's velocity changes.

Option-B.

<u>Explanation:</u>

As the car is moving in the circular motion, its velocity changes, as its speed is scalar and which means it is constant, velocity changes (being a vector quantity).

Its angular velocity is the speed in the direction of the curve the vehicle moves, which means it is constant, but is acted upon by an acceleration toward its center called centripetal acceleration and it is necessary to maintain the circular motion of the car.

Sergeeva-Olga [200]3 years ago
7 0

Answer:C) both its speed and its velocity.

Explanation:

changing one but not the other would cause a spin out and crash

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Dana is trying to determine if an unknown sample is a pure substance or not. The sample has a cloudy white color, and it seems e
Firdavs [7]

Answer:

Dana filtered the sample and larger granules of the sample were left behind.

Explanation:

If a substance is pure, it will have a uniform composition throughout. It will not separate into particles of various sizes.

One of the characteristics of pure substances is that they are homogeneous. A mixture is definitely made up of particles of various sizes.

Since the particles was filtered and larger granules were left behind, the sample has been separated by a physical method (filtration). Only a mixture can be separated by physical methods. It is not a pure substance.

5 0
2 years ago
What is the predominant intermolecular force in CBr4
vovikov84 [41]
CBr4 is a symmetric tetrahedral molecule so it will be non-polar.
3 0
3 years ago
A sample of Mo(NO3)6 has 2.22 x 10^22 nitrogen atom, how many oxygen atoms does the sample have?
goldfiish [28.3K]

There are 3.98 × 10^23 atoms of oxygen in the sample.

Given that;

1 mole of Mo(NO3)6 contains 6.02 × 10^23 atoms of Nitrogen

x moles of Mo(NO3)6 contains 2.22 x 10^22 atoms of nitrogen

x = 1 mole × 2.22 x 10^22 atoms/6.02 × 10^23 atoms

x = 0.0368 moles

The number of oxygen atoms in the sample is given by; 0.0368 × 6.02 × 10^23 × 18

Therefore, there are 3.98 × 10^23 atoms of oxygen in the sample.

Learn more: brainly.com/question/9743981

4 0
2 years ago
What is the reduction half equation of Fe(s)+ 2 HC2H3O2(aq) → Fe(C2H3O2)2(aq) + H2(g)
Sonbull [250]

Answer:

2 H⁺ + 2e = H₂    ( reduction )

Explanation:

Fe( s ) + 2 CH₃COOH = Fe ( OOCCH₃ ) ₂ + H₂

Fe( s ) = Fe⁺² + 2e     ( oxidation )

2 H⁺ + 2e = H₂    ( reduction )

4 0
3 years ago
4.00 g of sodium and 2.00 g of oxygen react according to the following balanced equation 4 Na + O2 → 2 Na2O Calculate the mass o
posledela
6.00g because it is a balanced equation
6 0
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