Answer:
A
Step-by-step explanation:
Answer:
1.16
Step-by-step explanation:
Given that;
For some positive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770.
This implies that:
P(0<Z<z) = 0.3770
P(Z < z)-P(Z < 0) = 0.3770
P(Z < z) = 0.3770 + P(Z < 0)
From the standard normal tables , P(Z < 0) =0.5
P(Z < z) = 0.3770 + 0.5
P(Z < z) = 0.877
SO to determine the value of z for which it is equal to 0.877, we look at the
table of standard normal distribution and locate the probability value of 0.8770. we advance to the left until the first column is reached, we see that the value was 1.1. similarly, we did the same in the upward direction until the top row is reached, the value was 0.06. The intersection of the row and column values gives the area to the two tail of z. (i.e 1.1 + 0.06 =1.16)
therefore, P(Z ≤ 1.16 ) = 0.877
The equation for inflation is
A = P*(1+r)^t
which is an exponential growth equation (if r > 0). If r < 0, then we have deflation.
where...
A = final price after t years
P = initial starting price
r = rate of inflation in decimal form
t = number of years
In this case,
A = unknown (we're solving for this)
P = 280 is the starting price
r = 0.05 is the decimal form of 5%
t = 2 years
We will plug these three pieces of info into the formula to get...
A = P*(1+r)^t
A = 280*(1+0.05)^2
A = 280*(1.05)^2
A = 280*(1.1025)
A = 308.70
Answer: 308.70 dollars
To calculate the square root, you can either use the √symbol on a calculator or you can manually find it using Prime Factorization. For non-perfect squares, Prime Factorization is the way to go.
The first two steps work for solving large perfect squares as well.
1. Divide your number into perfect square factors.
2. Take the square roots of your perfect square factors.
3. If your number doesn't factor perfectly, reduce your answer to simplest terms.
4. If needed, estimate. In some cases if you have memorized some of the square roots, you can estimate where the number would be.
ie.
![\sqrt{63}](https://tex.z-dn.net/?f=%20%5Csqrt%7B63%7D%20)
you know that
![7^2 =49](https://tex.z-dn.net/?f=7%5E2%20%3D49)
and
![8^2 = 64](https://tex.z-dn.net/?f=8%5E2%20%3D%2064)
, so you can estimate that the
![\sqrt{63}](https://tex.z-dn.net/?f=%20%5Csqrt%7B63%7D%20)
would be between 7 and 8 but closer to 8.
5. <span>Alternatively, reduce your number to its lowest common factors as your first step.</span><span> Finding perfect square factors isn't necessary if you can easily determine a number's prime factors (factors that are also prime numbers).
ie. </span>
![\sqrt{45}](https://tex.z-dn.net/?f=%20%5Csqrt%7B45%7D%20)
=
![\sqrt{9*5}](https://tex.z-dn.net/?f=%20%5Csqrt%7B9%2A5%7D%20)
=
![\sqrt{3*3*5}](https://tex.z-dn.net/?f=%20%5Csqrt%7B3%2A3%2A5%7D%20)
=
![3 \sqrt{5}](https://tex.z-dn.net/?f=3%20%5Csqrt%7B5%7D%20)
Hope this helped!!!