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yaroslaw [1]
3 years ago
10

Which of the following substances is NOT an acid?

Chemistry
1 answer:
galben [10]3 years ago
7 0

Answer: C is the answer

Explanation:

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Barium chloride bea CO2 is a binary compound because it contains
Tpy6a [65]

Answer:

Because it contains only two elements.

Explanation:

A binary compound is a compound made up of only two elements. Barium chloride contains:

1. Barium.

2. Chlorine.

Since Barium chloride contains only two elements, it is therefore a binary compound.

6 0
3 years ago
Write the correct name for each compound. a. N2O5 b. Si2F4 c. S3F d. OF2 e. H4P6 f. C2O4 g. HF3
PSYCHO15rus [73]

Answer:

a. Boron trifluoride

b. Propane

c. Dinitrogen pentoxide

d. Carbon Dioxide

e. Silicon Octafluroride?

Explanation:

Glad to help :)

3 0
3 years ago
Among important crop plants, nitrogen-fixing root nodules are most commonly an attribute of A) corn. B) legumes. C) wheat. D) me
7nadin3 [17]
<span>Among important crop plants, nitrogen-fixing root nodules are most commonly an attribute of
B) legumes</span>
3 0
3 years ago
What is the value of x in the measure of the angle?
Andrew [12]
The two angles would be both 41 degrees.
(2x  + 13) = 41 \\ 2x = 41 - 13 \\ 2x = 28 \\ x =  \frac{28}{2} \\ x = 14
x in this case would be 14 degrees.
4 0
3 years ago
Read 2 more answers
A lab technician mixes a 0.730 M solution of sodium bromide (NaBr) and water. The volume of the solution is 135 milliliters.
Ivenika [448]

Answer:

We need 10.14 grams of sodium bromide to make a 0.730 M solution

Explanation:

Step 1: Data given

Molarity of the sodium bromide (NaBr) = 0.730 M

Volume of the sodium bromide solution = 135 mL = 0.135 L

Molar mass sodium bromide (NaBr) = 102.89 g/mol

Step 2: Calculate moles NaBr

Moles NaBr = Molarity NaBr * volume NaBr

Moles NaBr = 0.730 M * 0.135 L

Moles NaBr = 0.09855 moles

Step 3: Calculate mass of NaBr

Mass NaBr = 0.09855 moles * 102.89 g/mol

Mass NaBr = 10.14 grams

We need 10.14 grams of sodium bromide to make a 0.730 M solution

3 0
3 years ago
Read 2 more answers
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