Consider the reaction between aluminum and oxygen in a closed container. The equation for this reaction is:
Answer:
D. For every 4 atoms of aluminum and 3 molecules of oxygen gas, 2 units of the compound of aluminum and oxygen are produced.
→ This is true. For every 4 atoms of aluminium and 3 molecules of oxygen 2 units of aluminiumoxide will be produced.
Explanation:
Step 1: The balanced equation
4Al + 3O2 → 2Al2O3
A. On the product side of the equation above, there are 2 atoms of aluminum and 3 atoms of oxygen.
→ This is false. On the product side (2Al2O3) we have 4 atoms of Al and 6 atoms of oxygen
B. The 3 in front of O2 represents 3 atoms of oxygen.
→ This is false. The 3 means 3 oxygen (O2) molecules. Each molecule contains 2 oxygen (O) atoms.
C. The number of atoms, molecules, and ions of reactants is equal to the number of atoms, molecules, and ions of the products.
→ This is false. the number of atoms in the reactants is the same as the number of atoms in the product. ... However, the number of molecules in the reactants and products are not the same. The number of molecules is not conserved during the reaction
D. For every 4 atoms of aluminum and 3 molecules of oxygen gas, 2 units of the compound of aluminum and oxygen are produced.
→ This is true. For every 4 atoms of aluminium and 3 molecules of oxygen 2 units of aluminiumoxide will be produced.
Given that 4.50 dm³ of Pb(NO₃)₂ is cooled from 70 °C to 18 °C, the
amount amount of solute that will be deposited is 1,927.413 grams.
<h3>How can the amount of solute deposited be found?</h3>
The volume of water 1.33 dm³ of water 70 °C.
The number of moles of Pb(NO₃)₂ that saturates 1.33 dm³ of water at 70 °C = 2.25 moles
At 18 °C, the number of moles of Pb(NO₃)₂ that saturates 1.33 dm³ of water = 0.53 moles
Therefore;
Number of moles of Pb(NO₃)₂ in 4.50 dm³ at 70 °C is therefore;
1.33 dm³ contains 2.25 moles.
Number of moles of Pb(NO₃)₂ in 4.50 dm³ at 70 °C ≈ 7.613 moles
Number of moles of Pb(NO₃)₂ in 4.50 dm³ at 18 °C is therefore;
1.33 dm³ contains 0.53 moles
Number of moles of Pb(NO₃)₂ in 4.50 dm³ at 18 °C ≈ 1.79 moles
The number of moles that precipitate out = The amount of solute deposited
Which gives;
Amount of solute deposited = 7.613 moles - 1.79 moles = 5.823 moles
The molar mass of Pb(NO₃)₂ = 207 g + 2 × (14 g + 3 × 16 g) = 331 g
The molar mass of Pb(NO₃)₂ = 331 g/mol
The amount of solute deposited = Number of moles × Molar mass
Which gives;
The amount of solute deposited = 5.823 moles × 331 g/mol =<u> 1,927.413 g </u>
Learn more about saturated solutions here:
Explanation:
Mass = volume × density
Mass = 652 cm³ × 21.45 g/cm³
= 13985.4 g
Explanation:
Answer:
Nuclear fusion is when two atomic nuclei combine and form one nucleus. Nuclear fusion generates all of the Sun's energy. Inward pulling by the Sun's gravity is counteracted by outward pushing by the Sun's nuclear fusion; this balance keeps the sun from collapsing or exploding.
Explanation: