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3 years ago

Please hurry this is due tomorrow morning

Chemistry

1 answer:

Llana [10]3 years ago

3 0

Answer: G Atom 1 and Atom 4.. hope this helps and good luck!

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Explain how/why you categorized the substances the way you did. What characteristics of the substances helped you predict whethe

Rasek [7]

The presence of hydrogen and hydroxyl ions determines the acidic and basic nature of a solution.

<h3>What determine acidic and basic nature of a solution?</h3>

The use of the pH scale is one way of determining the acidic and basic nature of solution. If the pH of a solution is less than 7, it is considered as acidic and if the pH is 7, the solution is neutral.

While if the pH is greater than 7,the solution is basic so we can conclude that the presence of hydrogen and hydroxyl ions determines the acidic and basic nature of a solution.

Learn more about substance here: brainly.com/question/2901507

6 0

2 years ago

HELP WILL GIVE BRANLIEST

klio [65]

Answer:

Explanation:

Sucrose and water are both compounds made up of more than one type of atom.

Water(H2O)= Hydrogen and Oxygen

Sucrose(C12H22O11)= Carbon Hydrogen & Oxygen

8 0

3 years ago

Read 2 more answers

I really need help anybody there ?

lesantik [10]

The answer is Fertility

3 0

3 years ago

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A compound contains 64 g of o and 8 g of h. what is the empirical formula for this compound?

kaheart [24]

The empirical formula is obtained by calculating the mole ratios of the atoms in the elements.
The number of moles =mass/ R.A.M
For hydrogen, no. of moles=8/1=8
For oxygen, no. Of moles=64/16=4
The tabular solution is attached.

6 0

3 years ago

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1. A chemist prepares hydrogen fluoride by means of the following reaction:

Natasha_Volkova [10]

Answer:

a) <em>Theoretical Yield of HF = 5.64 grams</em>

b) <em>Percentage Yield = 39%</em>

Explanation:

Reaction Given:

CaF2 + H2SO4 -> CaSO4 + 2HF

CaF2 = 11g

H2SO4 = Used in excess

HF = 2.2 g production = Actual Yield

So, Let's write down the molar masses:

Molar Mass of CaF2 = 78 g /mol

Molar Mass of HF = 20 g/mol

From the reaction, we can see the 1 mole of CaF2 gives the 2 moles of HF

i.e

a) Theoretical Yield of HF:

1 mole CaF2 = 2 moles HF

78 g CaF2 = 2 x 20 g of HF

78 g CaF2 = 40 g of HF

1 g CaF2 = 40g/78g of HF

And in the question it is given that chemist used 11 g of CaF2 so,

1 x 11 g of CaF2 = 11 x 40/78 g of HF

11 g of CaF2 = 440/78 g of HF

11 g of CaF2 = 5.64 g of HF

And this is the theoretical yield

<em>Theoretical Yield of HF = 5.64 grams</em>

b) Now, calculate the Percentage Yield of HF

<em>Percentage Yield = Actual Yield /Theoretical Yield x 100</em>

Percentage Yield = 2.2 g /5.64 g x 100

Percentage Yield = 39%

8 0

3 years ago