<h3>
Answer:</h3>
2.809 L of H₂SO₄
<h3>
Explanation:</h3>
Concept tested: Moles and Molarity
In this case we are give;
Mass of solid sodium hydroxide as 13.20 g
Molarity of H₂SO₄ as 0.235 M
We are required to determine the volume of H₂SO₄ required
<h3>First: We need to write the balanced equation for the reaction.</h3>
- The reaction between NaOH and H₂SO₄ is a neutralization reaction.
- The balanced equation for the reaction is;
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O
<h3>Second: We calculate the umber of moles of NaOH used </h3>
- Number of moles = Mass ÷ Molar mass
- Molar mass of NaOH is 40.0 g/mol
Moles of NaOH = 13.20 g ÷ 40.0 g/mol
= 0.33 moles
<h3>Third: Determine the number of moles of the acid, H₂SO₄</h3>
- From the equation, 2 moles of NaOH reacts with 1 mole of H₂SO₄
- Therefore, the mole ratio of NaOH: H₂SO₄ is 2 : 1.
- Thus, Moles of H₂SO₄ = moles of NaOH × 2
= 0.33 moles × 2
= 0.66 moles of H₂SO₄
<h3>Fourth: Determine the Volume of the acid, H₂SO₄ used</h3>
- When given the molarity of an acid and the number of moles we can calculate the volume of the acid.
- That is; Volume = Number of moles ÷ Molarity
In this case;
Volume of the acid = 0.66 moles ÷ 0.235 M
= 2.809 L
Therefore, the volume of the acid required to neutralize the base,NaOH is 2.809 L.
The correct answer to this is:
<span>Chondroitin sulfate is abundant in the matrix of <u>“Cartilage”.</u></span>
<span>A 1 unit of Chondroitin sulfate has a chemical formula of
C</span>13H21NO15<span>S. It is
usually found attached to proteins as part of a proteoglycan and is a vital
structure of cartilage by providing much resistance to compression. Due to
this, this chemical has found wide use as a dietary supplement for treatment of
osteoarthritis.</span>
Organism<span>. ' s rate of mutation is directly proportional to its adaptability. .... D. The cell membrane contains </span>genetic<span> information of the cell. .... </span>What<span> cellular structure was the dialysis tubing most likely</span>representing<span> in this experiment? ...... C </span>Rr<span> and </span>rr<span> only ... A healthy </span>individual<span> is a carrier of a lethal allele but is unaffected by it.</span>
It honestly depends weather or not they create them the same way
Answer:
= 498.13 mmHg
Explanation:
Using the combined gas law;
P1V1/T1 =P2V2/T2
in this case; P1 = 725 mmHg, V1 = 375 mL and T1 = 25°C + 273 = 298 K
P2 = ? V2 = 500 mL and T2 (standard temperature) = 0°C + 273 = 273 K
P2 = P1V1T2/T1V2
= (725 × 375 × 273)/(298 × 500)
<u>= 498.13 mmHg </u>
