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s344n2d4d5 [400]
3 years ago
6

Compare and contrast a compound light microscope and a transmission electron microscope. Be sure to discuss the structure and op

eration of each, as well as the function and usefulness of each when examining specimens.
Physics
1 answer:
Anna [14]3 years ago
8 0
<span>Transmission electron microscope -
 The transmission electron microscope uses electrons instead of light
. a light microscope is limited by the wavelength of light.
TEMs use electrons as "light source" and their much lower wavelength makes it possible to get a resolution a thousand times better than with a light microscope
. The possibility for high magnifications has made the TEM a valuable tool in both medical, biological and materials research.</span><span>Compound light microscope
- Microscope with more than one lens and its own light source
. There are ocular lenses in the bonicular eyepieces and objective lenses in a rotating nosepiece closer to the specimen. To ascertain the power of magnification of a compund light microscope, it's needed to take the power of the objective lens and multiply it by the eyepiece which is generally 10x. Although sometimes found as monocular with one ocular lens, the compound binocular microscope is more commonly used today. The first light microscope dates back to 1595, when Zacharias Jansen created a compound microscope that used collapsing tubes and produced magnifications up to 9X.


</span>
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Which statement best explains why the overall charge on an atom is zero?
aalyn [17]
A: The positive charge if the protons in the nucleus equals the negative charge in the electron cloud.


Protons are positive, electrons are negative, and neutrons have no charge/are neutral
3 0
3 years ago
An offshore oil well is 2 kilometers off the coast. The refinery is 4 kilometers down the coast. Laying pipe in the ocean is twi
shusha [124]

Answer:

Rectangular path

Solution:

As per the question:

Length, a = 4 km

Height, h = 2 km

In order to minimize the cost let us denote the side of the square bottom be 'a'

Thus the area of the bottom of the square, A = a^{2}

Let the height of the bin be 'h'

Therefore the total area, A_{t} = 4ah

The cost is:

C = 2sh

Volume of the box, V = a^{2}h = 4^{2}\times 2 = 128            (1)

Total cost, C_{t} = 2a^{2} + 2ah            (2)

From eqn (1):

h = \frac{128}{a^{2}}

Using the above value in eqn (1):

C(a) = 2a^{2} + 2a\frac{128}{a^{2}} = 2a^{2} + \frac{256}{a}

C(a) = 2a^{2} + \frac{256}{a}

Differentiating the above eqn w.r.t 'a':

C'(a) = 4a - \frac{256}{a^{2}} = \frac{4a^{3} - 256}{a^{2}}

For the required solution equating the above eqn to zero:

\frac{4a^{3} - 256}{a^{2}} = 0

\frac{4a^{3} - 256}{a^{2}} = 0

a = 4

Also

h = \frac{128}{4^{2}} = 8

The path in order to minimize the cost must be a rectangle.

8 0
4 years ago
Please help on this one?
vova2212 [387]

Answer: The system internal energy is 40 Joules.

Explanation: As suggested, the formula \Delta U = Q-W=(70-30)J = 40J should be used. 70 Joules worth of thermal energy are added, and the system does 30 Joules worth of work (energy expenditure).

7 0
3 years ago
Read 2 more answers
Which of the following best describes gravitational potential energy,
s2008m [1.1K]
The energy stored in an object when you lift it,
8 0
3 years ago
A uniform disk has a mass of 3.7 kg and a radius of 0.40 m. The disk is mounted on frictionless bearings and is used as a turnta
yuradex [85]

Answer:

1.25 kgm²/sec

Explanation:

Disk inertia, Jd =

Jd = 1/2 * 3.7 * 0.40² = 0.2960 kgm²

Disk angular speed =

ωd = 0.1047 * 30 = 3.1416 rad/sec

Hollow cylinder inertia =

Jc = 3.7 * 0.40² = 0.592 kgm²

Initial Kinetic Energy of the disk

Ekd = 1/2 * Jd * ωd²

Ekd = 0.148 * 9.87

Ekd = 1.4607 joule

Ekd = (Jc + 1/2*Jd) * ω²

Final angular speed =

ω² = Ekd/(Jc+1/2*Jd)

ω² = 1.4607/(0.592+0.148)

ω² = 1.4607/0.74

ω² = 1.974

ω = √1.974

ω = 1.405 rad/sec

Final angular momentum =

L = (Jd+Jc) * ω

L = 0.888 * 1.405

L = 1.25 kgm²/sec

5 0
3 years ago
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