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aalyn [17]
3 years ago
7

Cual es la fuerza de empuje que recibe un cuerpo de forma cilíndrica que mide 0.3 m de radio y 8m de altura, el cual se sumerge

en alcohol si su densidad es de 790 Km/m3 tomando en cuenta la gravedad de 9.8m/seg2
Physics
1 answer:
zimovet [89]3 years ago
3 0

Responder:

Fb = 17,5 kN

Explicación:

La expresión de la fuerza de empuje

Fb = ρgV ---------- 1

dónde

Fb = fuerza de flotación

ρ = densidad del fluido

g = aceleración debida a la gravedad

V = volumen de fluido

Paso uno:

datos dados

radio del cilindro = 0,3 m

altura h = 8m

densidad = 790 kg / m ^ 3

g = 9,8 m / s ^ 2

El volumen del cilindro se expresa como

V = πr ^ 2h

V = 3,142 * 0,3 ^ 2 * 8

V = 3,142 * 0,09 * 8

V = 2,26

El volumen es 2.26m ^ 3, el volumen del cilindro es igual al volumen de alcohol disparado

La expresión de la fuerza de empuje es

Fb = ρgV

sustituyendo tenemos

Fb = 790 * 9,8 * 2,26

Fb = 17514,26N

Fb = 17,5 kN

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Maurinko [17]

a. The ball's horizontal and vertical positions at time t are given by

x=\left(27.4\,\dfrac{\rm m}{\rm s}\right)t

y=2.34\,\mathrm m-\dfrac g2t^2

The ball reaches the net when x=12.0\,\rm m:

12.0\,\mathrm m=\left(27.4\,\dfrac{\rm m}{\rm s}\right)t\implies t=0.438\,\rm s

At this time, the ball is at an altitude of

2.34\,\mathrm m-\dfrac g2\left(0.438\,\mathrm s\right)^2=1.40\,\mathrm m

which is 1.40 m - 0.900 m = 0.500 m above the net.

b. The change in angle gives the ball the new position functions

x=\left(27.4\,\dfrac{\rm m}{\rm s}\right)\cos(-5.00^\circ)t

y=2.34\,\mathrm m+\left(27.4\,\dfrac{\rm m}{\rm s}\right)\sin(-5.00^\circ)t-\dfrac g2t^2

The ball reaches the net at time t such that

\left(27.4\,\dfrac{\rm m}{\rm s}\right)\cos(-5.00^\circ)t=12.0\,\mathrm m\implies t=0.440\,\mathrm s

at which point the ball's vertical position would be

2.34\,\mathrm m+\left(27.4\,\dfrac{\rm m}{\rm s}\right)\sin(-5.00^\circ)\left(0.440\,\mathrm s\right)-\dfrac g2\left(0.440\,\mathrm s\right)^2=0.343\,\mathrm m

so that the ball does not clear the net with 0.343 m - 0.900 m = -0.557 m.

5 0
3 years ago
What is meant by lateral inversion​
grandymaker [24]

Answer:

Explanation:

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4 0
3 years ago
1A.)A railroad car of mass 21700 kg moving with a speed of 3.36 m/s collides
Pepsi [2]

Answer:

(a) 2.03 m/s

(b) 2.15 m/s

Explanation:

(a)

From the law of conservation of momentum, the sum of initial momentum equals the sum of final momentum

Momentum, p=mv where m is the mass and v is the velocity

m_1v_1+m_2v_2=(m_1+m_2)v_c where v_c is the common velocity, v_1 and v_2 are velocities of the first railroad car  and the second railroad car respectively, m_1 and m_2 are masses of the first railroad car  and the second railroad car respectively

Substituting the given figures then

21700\times 3.36+41700\times 1.34=(21700+41700)v_c\\63400v_c=128790\\v_c=\frac {128790}{63400}=2.031388013\approx 2.03 m/s

(b)

Momentum, p=mv where m is the mass and v is the velocity

m_1v_1+m_2v_2=m_1v_3+m_2v_4 where v_1 and v_2 are initial velocities of the ball moving towards west and the other ball moving in opposite direction respectively, m_1 and m_2 are masses of the first railroad car  and the second railroad car respectively

Taking west as positive then the opposite direction will be negative hence

0.455\times 7.36+(1.01\times -12.4)= 0.455\times -15.4 + (1.01\times v_4}

Note that when the 0.455 rebounds, it moves towards East and since we took West as positive that is why we give 15.4 as a negative value.

-2.1682=1.01v_4\\v_4=\frac {-2.1682}{1.01}=-2.146732673\approx 2.15 m/s towards East

8 0
4 years ago
Which of these is an example of projectile motion?
Usimov [2.4K]

Answer:

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8 0
3 years ago
g The electric field in a sinusoidal wave changes as E =125 N>C2cos 311.2 * 1011 rad>s2t +14.2 * 102 rad>m2x] (a) In wh
Elan Coil [88]

Answer:

a) the propagation direction is x, b)   E₀ = 125 N / C² , c) B = 41.67 10⁻⁸ T ,

d)  f = 4.95 10¹¹ Hz, e)  λ = 4.42 10⁻³ m, f) the speed of light ,

Explanation:

The equation they give for the sine wave is

      E = 125 cos (14.2 10² x - 311.2 10¹¹ t)

This expression must have the general shape of a traveling wave

      E = Eo cos (kx - wt + Ф)

we can equal each term between the two equations

a) the propagation direction is x, since it is the term that accompanies the vector k

b) the amplitude is the coefficient before the cosine function

          E₀ = 125 N / C²

c) to find the amplitude of the magnetic field we use that the two fields are in phase

          C = E / B

          B = E / c

          B = 125/3 10⁸

          B = 41.67 10⁻⁸ T

d) the angular velocity is

          w = 311.2 10¹¹ rad / s

angular velocity and frequencies are related

          w = 2π f

           f = w / 2π

           f = 311.2 10¹¹ / 2π

           f = 4.95 10¹¹ Hz

e) the wavelength is obtained from the wave number

          k = 2π /λ

          k = 14.2 10² rad / m

          λ = 2π / k

          λ = 2π / 14.2 10²

          λ = 4.42 10⁻³ m

f) the speed of an electromagnetic wave is the speed of light

g) what is a transverse wave

4 0
3 years ago
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