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JulsSmile [24]
4 years ago
10

PLEASE HELP ASAPPPPPPPP

Mathematics
2 answers:
Dvinal [7]4 years ago
5 0
3.9 x 10 ^-5 is the answer. 0.000039 in scientific notation is 3.9 x 10^-5
Reil [10]4 years ago
5 0
<span>0.6(6.5x10^5)
= 0.6 x 6.5 + 0.6 x 10^5
= 3.9 + 60,000
= 60,003.9
= 6.00039 x 10^4</span>
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In a group of 100 people, 70 have a DVD player, 60 have a CD
erma4kov [3.2K]

Answer:

50 people

Step-by-step explanation:

100-70 is 30. 30-20 is 10. 60-10 is 50.

5 0
3 years ago
The swimming pool is open when the high temperature is higher than 20∘C. Lainey tried to swim on Monday and Thursday (which was
Sergeeva-Olga [200]

Answer:

30-3d\leq 20

Step by step explanation:

Let d represent the rate of temperature decrease in degrees Celsius per day from Monday to Thursday.  

As temperature decreased at a constant rate in the next 3 days, so the rate of temperature will decrease 3d degree Celsius in 3 days.  

We are told that the pool was open on Monday. The high temperature was 30^oC on Monday. So the decrease in temperature from Monday to Thursday will be 30-3d.

We have been given that the swimming pool is open when the high temperature is higher than 20^oC.

As the pool was closed on Thursday. This means that temperature on Thursday was less than or equal to 20 degree Celsius. We can represent this information in an inequality as:

30-3d\leq 20

Therefore, the inequality 30-3d\leq 20 can be used to determine the rate of temperature decrease in degrees Celsius per day, d, from Monday to Thursday.

7 0
3 years ago
Read 2 more answers
I really need help pleaseee on the ones I got wrong
Pachacha [2.7K]

Answer:

7. 2|x+2|-1

8. (-2,-1)

10. y≥2

Step-by-step explanation:

7. a|x-h|+k

Vertical stretch by a factor of two, horizontal shift left two, vertical shift down one

8. (h,k)

10. It should be y, but otherwise you are good

8 0
4 years ago
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Elena-2011 [213]
Hope this will help you.

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3 years ago
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andrezito [222]

Answer:

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Step-by-step explanation:

Multiply the mass value by 16 to find the ounce.

Hope it helps. Merry Christmas and Happy asking! :)

6 0
4 years ago
Read 2 more answers
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