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2 years ago

What is the 3rd equivalent fraction to 2/5 ?

Mathematics

1 answer:

mezya [45]2 years ago

7 0

2/5
4/10
6/15

have a good day

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Find the volume of the following. Please round your answer to the nearest tenth. Please do not put units. Hint: You need to use

Sophie [7]

Answer:

Step-by-step explanation:

<u>The Volume of a Square Pyramid</u>

Given a square-based pyramid of base side a and height h, the volume can be calculated with the formula:

$\displaystyle V=\frac{1}{3}a^2h$

We are given a square pyramid with a base side a=14 ft but we're missing the height. It can be calculated by using the right triangle shown in the image attached below, whose hypotenuse is 25 ft and one leg is 7 ft

We use Pythagora's theorem:

$25^2=h^2+7^2$

Solving for h:

$h^2=25^2-7^2=625-49=576$

$h=\sqrt{576}=24$

The height is h=24 ft. Now the volume is calculated:

$\displaystyle V=\frac{1}{3}*14^2*24$

V = 1,568

3 0

2 years ago

Polynomial in standard form.

nataly862011 [7]

Answer:

-2x² - 8x - 15

Step-by-step explanation:

-(2x² + 4x + 11) + (-4)

-2x² - 8x - 11 - 4

-2x² - 8x - 15

6 0

3 years ago

ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. I say no guessing because people usually g

vredina [299]

Answer:

Range : { -3,0,4,6}

Step-by-step explanation:

The range of the function is the output values

Range : { -3,0,4,6}

5 0

3 years ago

Read 2 more answers

100 POINTS PLEAS please help

Kamila [148]

Answer:

$\textsf{A)} \quad 5u^3-2u^2+5u+8$

Step-by-step explanation:

Given expression:

$(-2u^3+5u-1)+(7u^3-2u^2+9)$

Remove parentheses:

$\implies -2u^3+5u-1+7u^3-2u^2+9$

Collect like terms:

$\implies -2u^3+7u^3-2u^2+5u-1+9$

Combine like terms:

$\implies 5u^3-2u^2+5u+8$

6 0

1 year ago

Read 2 more answers

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Temka [501]

Answer:

It diverges.

Step-by-step explanation:

We are given the inetegral: $\int\limits^{\infty}_2 \frac{1}{x} (\ln x)^2 dx$

$\int\limits^{\infty}_2 \frac{1}{x} (\ln x)^2 dx=\int\limits^{\infty}_2 (\ln x)^2 d(\ln x)=\\\\=\lim_{t \to \infty} \int\limits^t_2 (\ln x)^2d(\ln x)=\lim_{t \to \infty} \frac{(\ln t)^3}{3} |^t_2=\infty-\frac{(\ln 2)^3}{3} =\infty$

So it is divergent.

7 0

3 years ago