Answer:1.28v/k
Explanation:
Thermoelectric power is the same as Seebeck coefficient.
So the formula is S =Vemf/Th - Tl
= 12.8/310-300
S= 12.8/10
=1.28V/T
Answer:
Explanation:
Given
ambient Pressure =98.10 kPa
(a)gauge pressure 152 kPa
we know
Absolute pressure=gauge pressure+Vacuum Pressure
=152+98.10=250.1 kPa or 36.27 psi
(b)
=67.5 Torr or 8.99 kpa
as 1 Torr is 0.133 kPa
=8.99+98.10=107.09 kPa or 15.53 psi
(c)
=0.1 bar or 10 kPa
Thus absolute pressure=98.10-10=88.10 kPa or 12.77 psi
as 1 kPa is equal to 0.145 psi
(d)=0.84 atm or 85.113 kPa
as 1 atm is equal to 101.325 kPa
=98.10-85.11=12.99 kPa or 1.88 psi
Explanation:
This problem seeks to ensure that the student comprehends the meaning of precision and accuracy.
These two key terms are used to express how reliable experimental values obtained are.
- Precision is the ability to consistently reproduce a result.
- Accuracy is the nearness of the measure value to the true value.
- The different between the measured and true values gives the error in the result.
In the problem given, the most accurate reading would be one that has value close to the standard mass of 150g. Any student that reports this value would be reported as accurate.
The precise reading would be for the student that is able to repeatedly produce the same kind of values. This is irrespective of whether the values are close to the true value or not.
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Explanation:
v ^2 - u ^2 = 2 a s
- u ^2 = 2 * - 9.8 * 0.411
- u ^2 = - 8.0556
u = √8.0556
u = 2.83 m / sec
