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3 years ago

The Chandra X-ray observatory is BEST equipped to search for which types of stars? Select all that apply.

2 answers:

3 0

The right answer for the question that is being asked and shown above is that: "A. neutron; B. red giants; C. black holes; E. main sequence." The Chandra X-ray observatory is BEST equipped to search for neutron, red giants, black holes, main sequence.

prisoha [69]3 years ago

3 0

If you want the BEST, then you only get one of them.
If there were two different BESTs, then we would have to decide
whether one best is bester than the other best or whether they're
both equally best.

Red giants, white dwarfs, and main sequence stars are not
particularly strong emitters of X-rays, but they do emit lots of
other stuff that makes them easy to find.

Black holes don't emit anything, so no matter what kind of detector
you're using, they're tough to find.

Neutron stars are strong emitters of X-rays and not much else.
So an X-ray detector is just the thing to use to find them.

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Which force acts as an object to move it from rest or a constant straight line motion

sleet_krkn [62]

Answer:

The force is Inertia

Explanation:

The force that acts on an object to move it from rest or a constant straight line motion is known as Inertia.

In physics the above statement is governed by Newton's first law of motion which is also known as Law of Inertia.

This law states that, an object that is at rest will remain at rest and an object that is moving will continue to move in a straight line with constant speed, if and only if the net force acting on the object is zero.

This implies that, A stationary object will remain motionless if no force acts on it while a object with constant velocity will continue moving with constant velocity until a force acts on it (neglecting resistance from air and friction).

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2 years ago

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The radial velocity method preferentially detects: Choose one: A. all of the above described planets equally well. B. small plan

Zina [86]

The radial velocity method preferentially detects large planets close to the central star

what is the Radial velocity:

The radial velocity technique is able to detect planets around low-mass stars, such as M-type (red dwarf) stars.

This is due to the fact that low mass stars are more affected by the gravitational tug of planets.

When a planet orbits around a star, the star wobbles a little.

From this, we can determine the mass of the planet and its distance from the star.

hence we can say that,

option D is correct.

The radial velocity method preferentially detects large planets close to the central star

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1 year ago

What two types of evidence are used to classify orgianisms?

jeyben [28]

One is their traits and their characterists that they have in common

6 0

3 years ago

Read 2 more answers

Which statement correctly defines power?

Anna007 [38]

Answer:

$Power=V\, I$ which corresponds to the second option shown: "voltage times amperage"

Explanation:

The electric power is the work done to move a charge Q across a given difference of potential V per unit of time.

Since such electrical work is the product of the potential difference V times the charge that moves through that potential, and this work is to be calculated by the unit of time, we need to divide the product by time (t) which leads to the following final simple equation:

$Power=\frac{V\,Q}{t} =V\,\frac{Q}{t} = V\, I$

Notice that we replaced the quotient representing charge per unit of time (Q/t) by the actual current running through the circuit.

This corresponds to the second option shown in the question: "Voltage times amperage".

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3 years ago

To store stacks of clean plates, a cafeteria uses a closed cart with a spring-loaded shelf inside. Customers can take plates off

ruslelena [56]

The answer for the following problem is mentioned below.

The option for the question is "A" approximately.

Therefore the elastic potential energy of the string is 20 J.

Explanation:

Given:

Spring constant (k) = 240 N/m

amount of the compression (x) = 0.40 m

To calculate:

Elastic potential energy (E)

We know;

According to the formula;

E = $\frac{1}{2}$ × k × x × x

E = $\frac{1}{2}$ × k ×(x)²

where;

E represents the elastic potential energy

K represents the spring constant

x represents amount of the compression in the string

So therefore,

Substituting the values in the above formula;

E = $\frac{1}{2}$ × 240 × (0.40)²

E = $\frac{1}{2}$ × 240 × 0.16

E = $\frac{1}{2}$ × 38.4

E = 19.2 J or approximately 20 J

Therefore the elastic potential energy of the string is 20 J.

5 0

2 years ago