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3 years ago

The Chandra X-ray observatory is BEST equipped to search for which types of stars? Select all that apply.

2 answers:

3 0

The right answer for the question that is being asked and shown above is that: "A. neutron; B. red giants; C. black holes; E. main sequence." The Chandra X-ray observatory is BEST equipped to search for neutron, red giants, black holes, main sequence.

prisoha [69]3 years ago

3 0

If you want the BEST, then you only get one of them.
If there were two different BESTs, then we would have to decide
whether one best is bester than the other best or whether they're
both equally best.

Red giants, white dwarfs, and main sequence stars are not
particularly strong emitters of X-rays, but they do emit lots of
other stuff that makes them easy to find.

Black holes don't emit anything, so no matter what kind of detector
you're using, they're tough to find.

Neutron stars are strong emitters of X-rays and not much else.
So an X-ray detector is just the thing to use to find them.

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pishuonlain [190]

Answer:

$E_{total}=4.82*10^6N/C$

vector with direction equal to the axis X.

Explanation:

We use the Gauss Law and the superposition law in order to solve this problem.

Superposition Law: the Total Electric field is the sum of the electric field of the first infinite sheet and the Electric field of the second infinite sheet:

$E_{total}=E_1+E_2$

Thanks Gauss Law we know that the electric field of a infinite sheet with density of charge σ is:

$E=\sigma/(2\epsilon_o)$

Then:

$E_{total}=(\sigma_1+\sigma_2)/(2\epsilon_o)=(-2.7*10^{-6}+88*10^{-6})/(2*8.85*10^{-12})=4.82*10^6N/C$

This electric field has a direction in the axis perpendicular to the sheets, that means it has the same direction as the axis X.

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3 years ago

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AleksandrR [38]

Answer:

Hits per second=199 hit/s

Explanation:

#Given the angular velocity, $\omega=33\frac{1}{3} rev/min$ , radius of the record $r=0.1m$ and the distance between any two successive bumps on the groove as $d=1.75mm$ .

The linear speed of the record in meters per second is:

$v=\omega r=33\frac{1}{3}\times\frac{2\pi}{60}\times 10\times 10^{_2}\\\\=0.3843m/s\\$

#From $v$ above, if the bumps are uniformly separated by 1m, then the rate at which they hit the stylus is:

$Hits/second=v/d \ \ \ \ d=1.75mm\\\\=0.3483/0.000175\\\\=199.0385714\approx 199$

Hence the bumps hit the stylus at around 199hit/s

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the correct choice is

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Margaret [11]

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