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Evgen [1.6K]
3 years ago
8

What is responsible for the distribution of charge in conductors and insulators?

Physics
2 answers:
gladu [14]3 years ago
8 0
The answer is C:electron movement
inn [45]3 years ago
5 0

Answer:

C

electron movement

Explanation:

The electron is a subatomic particle, symbol 

e−

 or 

β−

, whose electric charge is negative one elementary charge.[9] Electrons belong to the first generation of the lepton particle family,[10] and are generally thought to be elementary particles because they have no known components or substructure.[1] The electron has a mass that is approximately 1/1836 that of the proton.[11] Quantum mechanical properties of the electron include an intrinsic angular momentum (spin) of a half-integer value, expressed in units of the reduced Planck constant, ħ. Being fermions, no two electrons can occupy the same quantum state, in accordance with the Pauli exclusion principle.[10] Like all elementary particles, electrons exhibit properties of both particles and waves: they can collide with other particles and can be diffracted like light. The wave properties of electrons are easier to observe with experiments than those of other particles like neutrons and protons because electrons have a lower mass and hence a longer de Broglie wavelength for a given energy.

Electrons play an essential role in numerous physical phenomena, such as electricity, magnetism, chemistry and thermal conductivity, and they also participate in gravitational, electromagnetic and weak interactions.[12] Since an electron has charge, it has a surrounding electric field, and if that electron is moving relative to an observer, said observer will observe it to generate a magnetic field. Electromagnetic fields produced from other sources will affect the motion of an electron according to the Lorentz force law. Electrons radiate or absorb energy in the form of photons when they are accelerated. Laboratory instruments are capable of trapping individual electrons as well as electron plasma by the use of electromagnetic fields. Special telescopes can detect electron plasma in outer space. Electrons are involved in many applications such as electronics, welding, cathode ray tubes, electron microscopes, radiation therapy, lasers, gaseous ionization detectors and particle accelerators.

Interactions involving electrons with other subatomic particles are of interest in fields such as chemistry and nuclear physics. The Coulomb force interaction between the positive protons within atomic nuclei and the negative electrons without, allows the composition of the two known as atoms. Ionization or differences in the proportions of negative electrons versus positive nuclei changes the binding energy of an atomic system. The exchange or sharing of the electrons between two or more atoms is the main cause of chemical bonding.[13] In 1838, British natural philosopher Richard Laming first hypothesized the concept of an indivisible quantity of electric charge to explain the chemical properties of atoms.[3] Irish physicist George Johnstone Stoney named this charge 'electron' in 1891, and J. J. Thomson and his team of British physicists identified it as a particle in 1897 during the cathode ray tube experiment.[5] Electrons can also participate in nuclear reactions, such as nucleosynthesis in stars, where they are known as beta particles. Electrons can be created through beta decay of radioactive isotopes and in high-energy collisions, for instance when cosmic rays enter the atmosphere. The antiparticle of the electron is called the positron; it is identical to the electron except that it carries electrical charge of the opposite sign. When an electron collides with a positron, both particles can be annihilated, producing gamma ray photons.

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The most abundant climate type over the face of the earth is
erastovalidia [21]
It is Humid Continental but i could be wrong
7 0
3 years ago
2) A skier stands at rest and begins to ski downhill with an acceleration of 3.0 m/s² {downhill). What is
Finger [1]

Answer:

337.5m

Explanation:

<u>Kinematics</u>

Under constant acceleration, the kinematic equation holds:

s=\frac{1}{2}at^2+v_ot+s_o, where "s" is the position at time "t", "a" is the constant acceleration, "v_o" is the initial velocity, and s_o is the initial position.

<u>Defining Displacement</u>

Displacement is the difference in positions: s-s_o or \Delta s
s=\frac{1}{2}at^2+v_ot+s_o

s-s_o=\frac{1}{2}at^2+v_ot

\Delta s=\frac{1}{2}at^2+v_ot

<u>Using known information</u>

Given that the initial velocity is zero ("skier stands at rest"), and zero times anything is zero, and zero plus anything remains unchanged, the equation simplifies further to the following:

\Delta s=\frac{1}{2}at^2+v_ot

\Delta s=\frac{1}{2}at^2+(0)*t

\Delta s=\frac{1}{2}at^2+0

\Delta s=\frac{1}{2}at^2

So, to find the displacement after 15 seconds, with a constant acceleration of 3.0 m/s², substitute the known values, and simplify:

\Delta s=\frac{1}{2}at^2

\Delta s=\frac{1}{2}(3.0[\frac{m}{s^2}])(15.0[s])^2

\Delta s=337.5[m]

5 0
2 years ago
A model rocket blasts off and moves upward with an acceleration of 12 m/s2 until it reaches a height of 26 m. at that height, it
Diano4ka-milaya [45]

initial acceleration of rocket is given as

a = 12 m/s^2

h = 26 m

now we can use kinematics to find its speed

v_f^2 - v_i^2 = 2 a h

v_f^2 - 0 = 2 * 12*26

v_f = 24.98 m/s

now after this it will be under free fall

so now again using kinematics

v_f = 0

at maximum height

v_f^2 - v_i^2 = 2 a s

0 - 24.98^2 = 2 * (-9.8)* h

h = 31.8 m

total height from the ground = 31.8 + 26 = 57.8 m

Part b)

now after reaching highest height it will fall to ground

So in order to find the speed we can use kinematics again

v_f^2 - v_i^2 = 2 a d

v_f^2 - 0 = 2*9.8*57.8

v_f = 33.67 m/s

Part c)

first rocket accelerate to reach height 26 meter and speed becomes 24.98 m/s

now we have

v_f - v_i = a t

24.98 - 0 = 12*t_1

t_1 = 2.1 s

after this it will reach to highest point and final speed becomes zero

v_f - v_i = at

0 - 24.98 = -9.8 * t

t_2 = 2.55 s

now from this it will fall back to ground and reach to final speed 33.67 m/s

now we have

v_f - v_i = at

33.67 - 0 = 9.8 * t

t_3 = 3.44 s

so total time is given as

<em>t = 3.44 + 2.55 + 2.1 = 8.1 s</em>

5 0
3 years ago
How do defy gravity?
kaheart [24]
Exert force upward.
Like when you pick something up from the floor, or walk up the stairs.
6 0
4 years ago
At locations A and B, the electric potential has the values VA=1.51 VVA=1.51 V and VB=5.81 V,VB=5.81 V, respectively. A proton r
Oksana_A [137]

Answer:

<u>For proton:</u>

A. The proton is released from Vb (highest potential)

B. v = 2.9x10⁴ m/s

<u>For electron:</u>

A. The electron is released from Va (lowest potential)

B. v = 1.2x10⁶ m/s    

Explanation:

<u>For a proton we have</u>:

A. To find the origin from which the proton was released we need to remember that in a potential difference, a proton moves from the highest potential to the lowest potential.                

Having that:

Va = 1.51 V and Vb = 5.81 V

We can see that the proton moves from Vb to Va, hence the proton was released from Vb.

B. We now that the work done by an electric field is given by:

W = \Delta Vq    (1)                                        

Where:

q: is the proton's charge = 1.6x10⁻¹⁹ C    

V: is the potential    

Also, the work is equal to:

W = \Delta K = (K_{a} - K_{b}) = \frac{1}{2}mv_{a}^{2} - \frac{1}{2}mv_{b}^{2}     (2)      

Where:

K: is the kinetic energy

m: is the proton's mass = 1.67x10⁻²⁷ kg

v_{a}: is the velocity in the point a

v_{b}: is the velocity in the point b = 0 (starts from rest)

Matching equation (1) with (2) we have:

\Delta Vq = \frac{1}{2}mv_{a}^{2}

(5.81 V - 1.51 V)*1.6 \cdot 10^{-19} C = \frac{1}{2}1.67 \cdot 10^{-27} kg*v_{a}^{2}

v_{a} = 2.9 \cdot 10^{4} m/s

<u>For an electron we have</u>:

A. For an electron we know that it moves from the lowest potential (Va) to the highest potential (Vb), so it is released from Va.

B. The speed is:

\Delta Vq = \frac{1}{2}mv_{b}^{2} - \frac{1}{2}mv_{a}^{2}

Since v_{a} = 0 (starts from rest) and m_{e} = 9.1x10⁻³¹ kg (electron's mass), we have:

(5.81 V - 1.51 V)*1.6 \cdot 10^{-19} C = \frac{1}{2}9.1 \cdot 10^{-31} kg*v_{b}^{2}    

v_{b} = 1.2 \cdot 10^{6} m/s

I hope it helps you!

6 0
4 years ago
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