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makvit [3.9K]
3 years ago
11

If 7r-2p/5=8p,what is the volume of 3r^2

Mathematics
1 answer:
Irina18 [472]3 years ago
7 0
It's
\frac{108p^{2} }{25}
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Please answer 100 points<br> Divide. 6 from 3/5 <br> 10<br> 30<br> 20<br> 15
almond37 [142]

Answer:

Step-by-step explanation:

What is 6 divided by 3/56 ÷ 3 5. The trick to working out 6 divided by 3/5 is similar to the method we use to work out dividing a fraction by a whole number. ... 6 x 5 3 = 30 3. So, the answer to the question "what is 6 divided by 3/5?" ... 30 3. ... 10 1. ... 10 1 = 10.

5 0
2 years ago
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An environmental group at a local college is conducting independent tests to determine the distance a particular make of automob
melomori [17]

Answer:

26.5265

Step-by-step explanation:

<u>Confidence Interval</u>

When the population standard deviation \sigma is known, the formula for a confidence interval for a population mean \bar x is:

\displaystyle \bar x \pm z\frac{\sigma}{\sqrt{n}}

Where n is the sample size and z is the corresponding z-value from the standard normal distribution for the selected confidence level. The value of z for a 95% confidence interval is z=1.96. The rest of the values are

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Calculating the confidence interval

\displaystyle 28.2 \pm 1.96\frac{2.7}{\sqrt{10}}

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Or, equivalently

26.5265

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3 years ago
Find the value of x.<br> (3x+20) º<br> 12°
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Answer:

x=32°

Step-by-step explanation:

2x+3x+20=180 co interior angle

5x=180-20

x=160/5=32°

7 0
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Consider this expression:
Tema [17]
8(4a+2b)
The equivalent is 32a+16b (B)

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3 years ago
SOMEONE HELP ME ASAP PLZZ!!!
Black_prince [1.1K]

Answer:

The distance of the plane from the base of the tower is 25.5 foot.

Step-by-step explanation:

As given

Max is in a control tower at a small airport.

He is located 50 feet above the ground when he spots a small plane on the runway at an angle of depression of 27°.

Now by using the trigonometric identity.

tan\theta = \frac{Perpendicular}{Base}

As shown in the figure given below

Perpendicular = CB

Base = AC = 50 feet

\theta = 27^{\circ}

Put in the identity.

tan\ 27^{\circ} = \frac{CB}{AC}

tan\ 27^{\circ} = \frac{CB}{50}

tan\ 27^{\circ} = 0.51\ (Approx)

Put in the above

0.51 = \frac{CB}{50}

CB = 0.51 × 50

CB = 25.5 foot

Therefore the distance of the plane from the base of the tower is 25.5 foot.


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3 years ago
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