Answer:
The inverse is y = x + 5
Step-by-step explanation:
The general equation of a straight line is;
y = mx + c
In this case , the y-intercept is -5
So the partial equation is;
y = mx - 5
To get m, we use the x-intercept
The x-intercept coordinate is (5,0)
Insert this in the equation , we have;
0 = 5m-5
5m = 5
m = 5/5
m= 1
The equation of the line is thus;
y = x-5
So we want to find the inverse of this;
Replace x with d
y = d-5
Make d the subject of the formula
d = y + 5
replace d with x
x = y + 5
now replace x with y
So we have
y = x + 5
Answer:
1) y = 5/2x - 3/2
2) y = 2/5x - 4/5
Step-by-step explanation:
1)
(1, 1) and (3, 6)
m = (y2 - y1)/(x2 - x1)
m= (6 - 1)/(3-1)
m= 5/2
m= 5/2
y - y1 = m(x - x1)
y - 1 = 5/2(x - 1)
y - 1 = 5/2x - 5/2
y = 5/2x - 3/2
2)
(2, 0) and (7, 2)
m = (y2 - y1)/(x2 - x1)
m= (2 - 0)/(7 - 2)
m = 2/5
y - y1 = m(x - x1)
y - 0 = 2/5(x - 2)
y = 2/5x - 4/5
Answer:
x=0.5355 or x=-6.5355
First step is to: Isolate the constant term by adding 7 to both sides
Step-by-step explanation:
We want to solve this equation: 
On observation, the trinomial is not factorizable so we use the Completing the square method.
Step 1: Isolate the constant term by adding 7 to both sides

Step 2: Divide the equation all through by the coefficient of
which is 2.

Step 3: Divide the coefficient of x by 2, square it and add it to both sides.
Coefficient of x=6
Divided by 2=3
Square of 3=
Therefore, we have:

Step 4: Write the Left Hand side in the form 

Step 5: Take the square root of both sides and solve for x

Answer:
The distance of the helicopter from the bristol is approximately 1<u>2.81 miles</u>
Step-by-step explanation:
Given:
Helicopter flies 10 miles east of bristol.
Then the helicopter flies 8 miles North before landing.
To find the direct distance between the helicopter and bristol.
Solution:
In order to find the distance of the helicopter from the bristol before landing, we will trace the path of the helicopter
The helicopter is first heading 10 miles east of bristol and then going 8 miles due north.
On tracing the path of the helicopter we find that the direct distance of the helicopter from the bristol is the hypotenuse of a right triangle formed by enclosing the path of the helicopter.
Applying Pythagorean theorem to find the hypotenuse of the triangle.



Taking square root both sides.

Thus, the distance of the helicopter from the bristol is approximately 12.81 miles