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NikAS [45]
3 years ago
5

Does changing the size of a substance affect its density

Chemistry
1 answer:
Romashka-Z-Leto [24]3 years ago
7 0

Answer:

yes

Explanation:

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Calculate the pH of the solution:<br> [OH-] = 1x10^-11M<br> a.11.0<br> b.12.0<br> c.2.7<br> d.3.0
Veronika [31]

p [OH-] = -log[OH-]= -log ( 1x10^-11M) = 11

we know that

p[OH-] + p[H+] = 14

so p[H+] = 14- p[OH-] = 14- 11 = 3

pH = 3, answer

6 0
3 years ago
Consider the equilibrium
Kamila [148]

Answer:

The answers are in the explanation

Explanation:

For the equilibrium:

B(aq) + H₂O(l) ⇌ HB⁺(aq) + OH⁻(aq).

By LeChatelier's principle, the increase in the concentration of a reactant (for example) at equilibrium will change the system counteracting the increasing producing more product.

Thus,

A) Will the equilibrium constant for the reaction increase, decrease, or stay the same? Why? .

The equilibrium constant is a thermodynamic constant that stay the same with the addition of a compound.

B) Will the concentration of HB⁺(aq) increase, decrease, or stay the same? Why?

By LeChatelier's principle, the addition of B will induce the formation of more HB⁺(aq) increasing the concentration.

C) Will the pH of the solution increase, decrease, or stay the same? Why?

As the addition of B induce the increasing of OH⁻, the pH of the solution will increase.

I hope it helps!

7 0
4 years ago
What is the formula of the compound between calcium and sulfur that has the percent composition 55.6% (by mass) calcium and 44.4
Gemiola [76]

Answer: The empirical formula is CaS

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of Ca= 55.6 g

Mass of S = 44.4 g  

Step 1 : convert given masses into moles.

Moles of Ca =\frac{\text{ given mass of Ca}}{\text{ molar mass of Ca}}= \frac{55.6g}{40.08g/mole}=1.38moles

Moles of S =\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{44.4g}{32.06g/mole}=1.38moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Ca = \frac{1.38}{1.38}=1

For S = \frac{1.38}{1.38}=1  

The ratio of Ca : S =  1:1  

Hence the empirical formula is CaS

7 0
3 years ago
How does one determine an empirical formula from a percent composition apex?
Amiraneli [1.4K]
To assume the empirical formula of a compound, you want the ratio of the moles of every element, and you discover that by means of the percent’s of the element as the element's mass.
As an instance, if a compound is 16% Carbon and 84% sulfur, you can round about that if you had a 100 gram sample of the compound, it would contain 16 grams of carbon & 84 grams of sulfur.
To look for the moles of carbon in that sample, you would distribute the mass by the atomic mass of carbon, so 16/12 = 1.3 moles. You do the similar calculation with the other elements. For Sulfur, you divide 84g by the atomic mass of sulfur, so 84/32 = 2.6moles of sulfur. You endure in this same way if there is more than 2 elements.
Lastly you find the ratio of the moles of every element. The unassuming way to do this is to look the element with the smallest number of moles and split the other moles by that number. In the above example 2.6 moles of Sulfur divided by 1.3 moles of Carbon equals 2. (Which is a 2:1 ratio) Therefore there is twice as numerous sulfurs as carbons in this compound, and the empirical formula is CS2.
8 0
3 years ago
Read 2 more answers
What statement best describes an independent variable?
Rzqust [24]
The answer is C. The independent variable is the factor that is changed by the experimenter and impacts the dependent variable.
7 0
3 years ago
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