What 2 numbers multiply to get -120, but add to get 2?

Is relation t a function? Is the inverse of relation t a function?

bonufazy [111]

Answer:

Hence, Relation t is a function. The inverse of relation t is a function.

Step-by-step explanation:

We are given the relation as:

x: 0 , 2 , 4 , 6

y: -10 , -1 , 4 , 8

Clearly from the y-values corresponding to the x-values we could see that each x has a single image (single y-value).

Hence, the corresponding relation is a function.

Now we have to find whether the inverse of this relation is a function or not.

When we take the inverse of this function that is the y-values will behave as a pre-image and x-values as its image.

Hence we will see that corresponding to each y-value there is a unique image hence the inverse relation is also a function.

Hence, Relation t is a function. The inverse of relation t is a function.

3 0

3 years ago

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Simplify the expression 5+6i/4+6i A) 56-6i/-20 B) -16-6i/-20 C)56-6i/52 D) -16-6i/52

IRISSAK [1]

Answer:

$The\ simplified\ form\ of\ the\ \frac{5 + 6i}{4 + 6i}\ is\ \frac{56-6i}{52}.$

Option (C) is correct .

Step-by-step explanation:

As the expression given in the question as follows.

$= \frac{5 + 6i}{4 + 6i}$

Now rationalize the expression.

$= \frac{5 + 6i\times 4 - 6i}{4 + 6i\times 4 - 6i}$

Using the formula

a² - b² = (a - b) (a + b)

Using in the above

$= \frac{5 + 6i\times 4 - 6i}{(4)^{2} - (6i)^{2}}$

$= \frac{5\times 4-5\times 6i+6i\times 4-36\ i^{2}}{16 - 36(i)^{2}}$

As i² = -1

$= \frac{20-30i+24i+36}{16 + 36}$

$= \frac{56-6i}{52}$

$Therefore\ the\ simplified\ form\ of\ the\ \frac{5 + 6i}{4 + 6i}\ is\ \frac{56-6i}{52}.$

Option (C) is correct .

8 0

2 years ago

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What number can go into 21 and 27

astra-53 [7]

3 only

Hope this helps

4 0

2 years ago

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How many terms are there in a geometric series if the first term is 4, the common ration is 3 and the sum of the series is 160

Marina CMI [18]

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=4\\
r=3\\
S_n=160
\end{cases}$

$\bf 160=4\left( \cfrac{1-3^n}{1-3} \right)\implies 160=4\left( \cfrac{1-3^n}{-2} \right)\implies 160=-2(1-3^n)
\\\\\\
160=2(3^n-1)\implies \cfrac{160}{2}=3^n-1\implies 80=3^n-1
\\\\\\
81=3^n~~
\begin{cases}
81=3\cdot 3\cdot 3\cdot 3\\
\qquad 3^4
\end{cases}\implies 3^4=3^n\implies 4=n$

3 0

2 years ago

What is the y-value when x equals 28? y=310-25(x)

Fofino [41]

Answer:

-390 PLEASE GIVE BRAINLIEST

Step-by-step explanation:

y = 310 - 25(28)

y = 310 - 700

y = -390

5 0

3 years ago