This isn't a good question but I guess!
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<span>Answer:
Hg2(NO3)2 + 2 NaCl --------> Hg2Cl2 + 2 NaNO3
Hg2+2 + 2NO3-1 + 2Na+ Cl- ----> Hg2Cl</span>
Answer:
"0.053457 M" of sulfuric acid.
Explanation:
The given values are:
= 10 mL solution
= 12.20 mL
= 22.20 mL
then,
M 0.103 M of NaOH,
= experiment will not be affected
= 10.38 mL
Now,
⇒ mol of NAOH = MV
= 
= 
Whether Sulfuric acid, then
⇒ 
⇒ 
⇒ 
Before any dilution:

⇒ 

(Sulfuric acid)