I don't agree with his statement. The first part says that he was paid $9.20 for the first 40 hours so we multiply them (9.20 x 40) to get 368. Then it says that he was paid 1.5 times that rate for every hour after that. The rate is "$9.20 per hour" so you find 1.5 times $9.20. You multiply $9.20 by 1.5 to get $13.80 per hour. Now you have to find how much money he got after the initial 40 hours. It says he worked 42.25 hours, and we already figured out how much money he got the first 40 hours ($368). So for the remaining 2.25 hours, Mr.Evens is paid $13.80 an hour. So we multiply 2.25 by $13.80 to get $31.05. To find out the total amount of money accumulated, we add. $368 + $31.05 is $399.05 which means that Mr.Evens is not correct. Hope this helped :]

7 0

3 years ago

Read 2 more answers

How can knowing the GCF and LCM help you when you add, subtract, and multiply fractions?

Stells [14]

When you add fractions, the denominators must be the same, so you may have to generate equivalent fractions by using the lowest common multiple of all the denominators. For subtraction of fractions, you use the same method. When multiplying fractions, you can only multiply the numerators together, and the denominators together.

6 0

3 years ago

Read 2 more answers

Hoping to lure more shoppers downtown, a city builds a new public parking garage in the central district. The city plans to pay

andrezito [222]

Answer:

a) For this case we need to use a t distribution since we know the information about a sample and we don't know the population deviation.

b) $126-1.77\frac{15}{\sqrt{14}}=118.904$

$126+1.77\frac{15}{\sqrt{14}}=133.096$

So on this case the 90% confidence interval would be given by (118.904;133.096)

c) For this case since confidence interval include tha value of 130 so then we don't have enough evidence to conclude that the claim by the consultant is incorrect.

Step-by-step explanation:

Part a

For this case we need to use a t distribution since we know the information about a sample and we don't know the population deviation.

Part b

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

$\bar X=126$ represent the sample mean

$\mu$ population mean (variable of interest)

s=15 represent the sample standard deviation

n=14 represent the sample size

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=14-1=13$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,13)".And we see that $t_{\alpha/2}=1.77$

Now we have everything in order to replace into formula (1):

$126-1.77\frac{15}{\sqrt{14}}=118.904$

$126+1.77\frac{15}{\sqrt{14}}=133.096$

So on this case the 90% confidence interval would be given by (118.904;133.096)

Part c

For this case since confidence interval include tha value of 130 so then we don't have enough evidence to conclude that the claim by the consultant is incorrect.

6 0

3 years ago

Yes, AA Yes, SAS Not similar Yes, SSS

Masteriza [31]

Answer:

Yes, AA

Step-by-step explanation:

These triangles are similar because 2 angles in each triangle are congruent.

8 0

3 years ago

The length of a square is 16m, what is the breadth of the square​

The length of a square is 16m, what is the breadth of the square