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egoroff_w [7]
3 years ago
8

Solve for x. 6^(x/2)=5^(1-x)

Mathematics
1 answer:
slavikrds [6]3 years ago
3 0

Hello from MrBillDoesMath!

Answer:

x = log5 / ( (1/2)log6 + log5)

    approximately  0.642

Discussion:

Take the logarithm of both sides ( to "pull" the exponents down so we can work on them!)

6^(x/2)) = 5^(1-x)

log ( 6^(x/2)) = log (5^(1-x))      =>   using log (a^n) = n log a

(x/2) log6 = (1-x) log5               =>   add x log5 to both sides

(x/2) log6 + xlog5 =  log5 - xlog5 + xlog5   =>

(x/2) log6 + xlog5 = log5          => factor x from the lhs

x (  (1/2) log6 + log5) = log5     =>

x = log5 / ( (1/2)log6 + log5)    

The above can be further simplified but that's as far as I want to take it.The value of x is approx equal to  0.642


Thank you,

MrB

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Required:

(a) Calculate the total value of products A, B and C which should be shown in inventory in the statement of financial position.

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Answer:

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a) Total value of products A, B, and C based on:

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b) The difference that changing from a weighted average to FIFO method of inventory valuation is likely to have on an entity's profit or loss:

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On the other hand, the FIFO method assumes that goods that are first to be in the store are the ones that are sold first.  This means that the cost of goods sold is valued at the cost of the first goods that are available for sale and the ending inventory is valued at the cost of newly purchased goods, since they are the ones that are still in stock by the FIFO assumption.

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Product B ​​​​    2,900          ​​​    2,800

Product C ​​​​    4,200           ​​    4,100

Valuation     10,700            12,000

Discounted 10,486            12,000

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