AB = CD = √8 ≈ 2.8 units
BC = AD = √2 ≈ 1.4 units
Area of the rectangle ABCD = 3.92 units²
Perimeter of the rectangle ABCD = 8.4 units
<h3>How to Find the Area and Perimeter of a Rectangle?</h3>
Given the coordinates of vertices of rectangle ABCD as:
- A(0,2)
- B(2,4)
- C(3,3)
- D(1,1)
To find the area and perimeter, use the distance formula to find the distance between A and B, and B and C.
Using the distance formula, we have the following:
AB = √[(2−0)² + (4−2)²]
AB = √[(2)² + (2)²]
AB = √8 ≈ 2.8 units
CD = √8 ≈ 2.8 units
BC = √[(2−3)² + (4−3)²]
BC = √[(−1)² + (1)²]
BC = √2 ≈ 1.4 units
AD = √2 ≈ 1.4 units
Area of the rectangle ABCD = (AB)(BC) = (2.8)(1.4) = 3.92 units²
Perimeter of the rectangle ABCD = 2(AB + BC) = 2(2.8 + 1.4) = 8.4 units
Learn more about the area and perimeter of rectangle on:
brainly.com/question/24571594
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2z +7 = -5
2z = -5 -7
2z = -12
z= -12 /2
z= -6
Answer:
-64
Step-by-step explanation:
Now we need to find out h(4)
to find h(4), we plug in 4 for x
Replace all x by 4 in h(x) and evaluate h(4)
So the value of f(4)= -64
Answer:
Step-by-step explanation:
If breadth =x
length =x+2
Area =length *breadth
Area =x(x+2)=80
X^2+2x-80=0
X^2 +10x - 8x - 80=0
X(x+10)- 8(x+10)=0
(X-8)(x+10)=0
X=8 or x=-10
X=8(since breadth cannot be a negative value x cannot be negative)
