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Leni [432]
3 years ago
8

Which reaction model represents a nuclear fission reaction?

Chemistry
2 answers:
julsineya [31]3 years ago
8 0

Answer: option B

Explanation: since nuclear fission involves the decay of larger nuclide into smaller nuclei along with Neutron when it is collide with Neutron.

Example Decay of U-235 into Kr and Ba along with 3 neutrons

11Alexandr11 [23.1K]3 years ago
4 0

Answer:

By presuming n denotes neutron, A is an atom and B & C are lighter nuclei, a reaction model of nuclear fission can be represented as follows:

n + A → B + C + n

Explanation:

A nuclear fission reaction is a process where a neuron collide with an atom and split it into two lighter nuclei and at the same time, a neuron and a large amount of energy will be released. The released neuron will then induce another nuclear fission on the next atom and repeat the same reaction process.

The understanding of nuclear fission play an important role in developing nuclear energy technology.

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Draw all the structural isomers for the molecular formula C3H8O. Be careful not to draw any structures by crossing one line over
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When an electron of a hydrogen atom travels from n = 4 to n = 2, a photon of energy 4.165 × 10-19 joules is released. Calculate
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4 0
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Read 2 more answers
Acetylene gas (ethyne; HC = CH) burns in an oxyacetylene torch to produce carbon dioxide and water vapor. The heat of reaction f
Yanka [14]

The mass of CO2 produced by 26g of acetylene is 88g.

Given ,

In an oxyacetylene torch, acetylene gas (ethyne; HCCH) burns to produce carbon dioxide and water vapour.

The acetylene combustion reaction is given by,

H2O + HCCH + 5/2 O=O 2CO2

Heat of reaction for acetylene combustion = 1259kj/mol

CO2 has a molecular mass of 44g/mol.

2 moles of CO2 have a molecular mass of 88g.

On combustion, 1 mole of acetylene yields 2 moles of CO2.

Thus, 26g of acetylene produces 88g of CO2 when burned.

As a result, the mass of carbon dioxide produced by 26g of acetylene is 88g.

Learn more about acetylene here :

brainly.com/question/15346128

#SPJ4

6 0
2 years ago
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