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marshall27 [118]
2 years ago
13

PLEASE HELP!!!

Chemistry
1 answer:
k0ka [10]2 years ago
6 0
3. Covalent/binary (not really sure)
4. Covalent
5. Ionic
6. Covalent
7. Acid
8. Ionic
9. Acid
10. Ionic
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You are running a rather large scale reaction where you prepare the grignard reagent phenylmagnesium bromide by reacting 210.14
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We would expect to form 7.35 moles of grignard reagent.

Explanation:

<u>Step 1: </u>Data given

Mass of magnesium = 210.14 grams

Volume bromobenzene = 772 mL

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<u>Step 2</u>: The balanced equation

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<u>Step 4</u>: Calculate number of moles bromobenzene

Moles bromobenzene = mass bromobenzene / molar mass bromobenzene

Moles bromobenzene = 1154.14g / 157.01 g/mol

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<u>Step 5:</u> Calculate moles of Mg

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<u>Step 6:</u> The limiting reactant

The mole ratio is 1:1 So the bromobenzene has the smallest amount of moles, so it's the limiting reactant. It will be completely consumed ( 7.35 moles). Magnesium is in excess, There will react 7.35 moles. There will remain 8.65 - 7.35 = 1.30 moles

<u>Step 7:</u> Calculate moles of phenylmagnesium bromide

For 1 mole of bromobenzene, we need 1 mole of Mg to produce 1 mole of phenylmagnesium bromide

For 7.35 moles bromobenzene, we have 7.35 moles phenylmagnesium bromide

We would expect to form 7.35 moles of grignard reagent.

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