Answer:The volume of the remaining gas that is ammonia is 23.85 L.
Explanation:
Moles of
Moles of HCl of gas =
According to reaction 1 mole of HCl reacts with 1 mol of then 2.06 moles of HCl will react with = 2.06 moles of
Moles left of ammonia left = 4.43 - 2.06 = 2.36 moles
Volume of the gas will be given by Ideal gas equation: PV=nRT
Pressure = 752 mmHg = 752 × 0.0031 atm = 2.33 atm
R = 0.08026 L atm/K mol
V = ? , n = number of moles of ammonia
Temperature = 14 °C = 14 + 273 K = 287 K(0°C = 273K)
The volume of the remaining gas that is ammonia is 23.85 L.
Answer:
Na2O+H2O=2NaOH
Step by step exp.
Given:
Equation Na2O+H2O=NaOH
To find: Balance the equation
Solution:
Taking LHS of the equation
LHS=Na2O+H2O
There is 2 sodium, 2 oxygen,& 2 hydrogen
To balance the equation we have equal number of atom so we multply 2 to the RHS=2NaOH
There fore the equation form is
Na2O+H2O=2NaOH
Answer:
The amount of moles of Fe in 5.22*10²² atoms of Fe is 0.0867.
Explanation:
Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression. Avogadro's number applies to any substance.
Then you can apply the following rule of three: if 6.023*10²³ atoms are contained in 1 mole, 5.22*10²² atoms are contained in how many moles?
amount of moles= 0.0867
<u><em>The amount of moles of Fe in 5.22*10²² atoms of Fe is 0.0867.</em></u>
Answer:
= <em>3</em><em>7</em><em> </em><em>g</em>
Explanation:
H₂SO₄ + 2NaOH ----> Na₂SO₄ + 2H₂O
2 moles of NaOH react with 1 mole of H₂SO₄
0.75 moles of NaOH will react with (0.75 / 2)×1
= 0.375 moles of H₂SO₄.
Formular mass of H₂SO₄ = (1×2)+32+(16×4) = 98g
1 mole of H₂SO₄ weighs 98g
0.375 moles of H₂SO₄ will weigh ( 0.375×98)g
= 36.7g = 37g of H₂SO₄