Answer:
7.613 kg
Explanation:
Since you need a ratio of 2 moles of LiOH for each mole of CO2, you can find the mass of LiOH that you need. The first thing that you need to do is to find the number of moles that 3.575 L of carbon dioxide gas is. At STP, there are 22.4 liters of gas in a mole, meaning that there are about 0.159 moles of carbon dioxide. Multiplying this by 2 you get 0.318 moles. The molar mass of LiOH can be calculated by adding together the molar masses of each of the constituents. Lithium has a molar mass of 6.941, oxygen has a molar mass of about 16, and hydrogen a molar mass of about 1. Adding this together you get a molar mass of 23.941kg, which for 0.318 moles is just 23.941*0.318=7.613 kg. Hope this helps, and PM me with questions!
Answer:
<span>The strongest intermolecular interactions between hydrogen fluoride (hf) molecules arise from Hydrogen Bonding.
Explanation:
Hydrogen Bond interactions are considered the strongest intermolecular interactions among molecules. These interactions are found between Hydrogen atom of one molecule bonded to most electronegative atoms (i.e F, O, N) and the most electronegative atoms of neighbor molecule.
In case of HF, fluorine has the greatest electronegativity of 4, so the hydrogen bonded to Fluorine becomes partial positive and makes Hydrogen bond with Fluorine atom of </span>neighbor HF molecule.<span />
Answer:
solid
Explanation:
It is called an amorphous solid because it lacks the ordered molecular structure of true solids, and yet its irregular structure is too rigid for it to qualify as a liquid.
Answer:
answer: Krypton
Explanation:
In bromine molecule bromine atom achieved Krypton electron configuration because before forming bromine molecule it had only 35 electron but after formaion molecule one elctron is shared by other bromine atom and after that bromine has 36 elecron which resembles with Krypton atomic number hence electronic configuration also achieved is same as Krypton.
Answer:
60.0mL of the diluted solution are needed
6.00mL of the 1.00M NaOH stock solution is the minimum volume needed to prepare the diluted solution.
Explanation:
As in each titration we need to use 20.0mL of the diluted 0.100M solution. As there are 3 titration, the volume must be:
3 * 20.0mL = 60.0mL of the diluted solution are needed
Now, to prepare a 0.100M NaOH solution from a 1.00M NaOH stock solution the dilution must be of:
1.00M / 0.100M = 10 times must be diluted the solution.
As we need at least 60.0mL, the minimum volume of the stock solution must be:
60.0mL / 10 times =
<h3>6.00mL of the 1.00M NaOH stock solution is the minimum volume needed to prepare the diluted solution.</h3>
