(2.00 hours) x (3,600 seconds/hour) = 7,200 seconds
(9.00 minutes) x (60 seconds/minute) = 540 seconds
The record time = (7,200 + 540 + 21) = 7,761 seconds
Distance = (speed) x (time)
= (5.436 m/s) x (7,761 sec) =<span> 42,188.8 meters
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The official length of the marathon run is 42,195 meters.
If we divide that by the record time in the question, we get
5.4368... m/s .
Rounded to the nearest thousandth, that's 5.437 m/s.
If the question had given the speed as 5.437 instead of 5.436 ,
then we would have calculated the distance to be
(5.437 m/s) x (7,761 sec) =<span> 42,196.6 meters,
4.6 meters closer to the official distance than the answer we did get.
</span>
Answer:
[M L2 T-2]
Explanation:
hope this is what you're looking for.
Answer:
S = 40.8m
Explanation:
<u>Given the following data;</u>
Initial velocity, u = 2m/s
Acceleration, a = 1.6m/s²
Time, t = 6secs
Required to find the displacement
Displacement, S = ?
The displacement of an object is given by the second equation of motion;

Where;
- S represents the displacement measured in meters.
- u represents the initial velocity measured in meters per seconds.
- t represents the time measured in seconds.
- a represents acceleration measured in meters per seconds square.
<em>Substituting into the equation, we have;</em>


S = 40.8m
<em>Therefore, the displacement of the skateboarder during this game is 40.8 meters. </em>
Answer:
The answer to this problem is 290.16m/s
Answer:
Here, m=10 kg
The resultant force acting on the body is
F=(98N)2+(6N)2=10N
Let the resultant force F makes an angle θ w.r.t. 8N force.
From figure, tanθ=8N6N=43
The resultant acceleration of the body is
a=mF=10kg10N=1ms−2
The resulatnt acceleration is along the direction of the resulatnt force.
Hence, the resultant acceleration of the body is 1 ms−2 at an angle of tan−1(43) w.r.t. 8N force.