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2 years ago

If you had started with a larger mass, how would the half-life change?

Physics

1 answer:

iogann1982 [59]2 years ago

3 0

Answer:

There is no change, unless your mass is somehow at the quantum level, at which the concept of half-life breaks down.

Half life is a property of the specific radioactive isotope...NOT of the initial sample's mass.

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1. How is electric potential energy similar to gravitational potential energy? How is it different? Where will an electron bound

Korolek [52]

Both ve similar equations
both are energies of one object w.r.t another 
differences- electric pe is due to electrostatic force and gravitational pe is due to gravitational force 
electric pe is > than gravitational pe since electrostatic force> gravitational force 
electron bound in an atom ll ve largest potential enegy in its ground state. i think hope it helps

7 0

2 years ago

according to Newton's __ law, an object with no net force acting on it remains at rest or in motion with a constant veloctiy

Pani-rosa [81]

Answer:

i think its his law of inertia

Explanation:

this law is about motion

5 0

2 years ago

A car is moving with the velocity of 90km/h. If the car come to rest after 10 seconds. Calculate the final velocity and distance

djyliett [7]

Answer:

you can learn from here

https://www.toppr.com/ask/en-bd/question/a-car-is-moving-with-a-velocity-of-10-ms-the-driver-sees-a-wall/

6 0

3 years ago

A rubber ball and a lump of clay have equal mass. They are thrown with equal speed against a wall. The ball bounces back with ne

gregori [183]

Answer:

The ball experiences the greater momentum change

Explanation:

The momentum change of each object is given by:

$\Delta p = m \Delta v= m (v-u)$

where

m is the mass of the object

v is the final velocity

u is the initial velocity

Both objects have same mass m and same initial velocity u. So we have:

- For the ball, the final velocity is

$v=-u$

Since it bounces back (so, opposite direction --> negative sign) with same speed (so, the magnitude of the final velocity is still u). So the change in momentum is

$\Delta p=m(v-u)=m((-u)-u)=-2mu$

- For the clay, the final velocity is

$v=0$

since it sticks to the wall. So, the change in momentum is

$\Delta p = m(v-u)=m(0-u)=-mu$

So we see that the greater momentum change (in magnitude) is experienced by the ball.

3 0

2 years ago

If he feels the chances of low, normal, and high precipitation are 30 percent, 20 percent, and 50 percent respectively, What is

Brilliant_brown [7]

Question:

The operations manager for a well-drilling company must recommend whether to build a new facility, expand his existing one, or do nothing. He estimates that long-run profits (in $000) will vary with the amount of precipitation (rainfall) as follows:

Alternative Precipitation

Low Normal High

Do nothing -100 100 300

Expand 350 500 200

Build new 750 300 0

If he feels the chances of low, normal, and high precipitation are 30 percent, 20 percent, and 50 percent respectively, What is EVPI (Expected value of Perfect Information)?

A. $140,000

B. $170,000

C. $285,000

D. $305,000

E. $475,000

Answer:

D. $170,000

Explanation:

The expected long run profits are for

Low Normal High

Do nothing -100*0.3 100*0.2 300*0.5 = 140

Expand 350*0.3 500*0.2 200*0.5 = 305

Build new 750*0.3 300*0.2 0*0.5 = 285

Therefore the expected long run profits are

$140,000

$305,000

$285,000

Based on his selected option being either to build new or to expand, the most profitable option is to expand

=$305,000

EVPI = EPPI-EMV =$170,000

7 0

3 years ago