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3 years ago

If you had started with a larger mass, how would the half-life change?

Physics

1 answer:

iogann1982 [59]3 years ago

3 0

Answer:

There is no change, unless your mass is somehow at the quantum level, at which the concept of half-life breaks down.

Half life is a property of the specific radioactive isotope...NOT of the initial sample's mass.

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Is the distance we walk equal to the magnitude of our displacement?

Yuliya22 [10]

Answer:

If you take the first example of the walk around the desk, it should be apparent that sometimes the distance is the same as the magnitude of the displacement. ... Since the displacement is measured along the shortest path between two points, its magnitude is always less than or equal to the distance.

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3 years ago

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2 years ago

The objective of baseball is to OUTSCORE your opponent.<br> True or false <br> Help ?

Yuki888 [10]

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3 years ago

Read 2 more answers

A body weighs 100newtons when submerged in water. calculate the upthrust action on the body

Andrews [41]

Answer:

Upthrust = 20 N

Explanation:

The question says that "A body weighs 100N in air and 80N when submerged in water. Calculate the upthrust acting on the body ?"

Upthrust is defined as the force when a body is submerged in liquid, then liquid applies a force on it.

ATQ,

Weight of body in air is 100 N

Weight of body in water is 80 N

Upthrust is equal to the weight of body in air minus weight of body in water.

Upthrust = 100 N - 80 N

Upthrust = 20 N

So, 20 N of upthrust is acting on the body.

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3 years ago

In a model AC generator, a 505 turn rectangular coil 8.0 cm by 30 cm rotates at 120 rev/min in a uniform magnetic field of 0.59

Ludmilka [50]

(a) Maximum emf: 90 V (2 sig. fig.)
(b) Emf at π/32 s: 85 V.
(c) t = 0.125 s.

<h3>Explanation</h3><h3>(a)</h3>

The maximum emf in the coil depends on

the maximum flux linkage through the coil, and
the angular velocity of the coil.

Maximum flux linkage in the coil:

$\phi_\text{max} = B\cdot A\cdot N = 0.59\;\text{T}\times(0.08 \times 0.30)\;\text{m}^{2} \times 505 = 7.2\;\text{Wb}$ .

Frequency of the rotation:

$f = 120\;\text{rev}\cdot\text{min}^{-1} = 2 \;\text{rev}\cdot\text{s}^{-1}$ .

Angular velocity of the coil:

$\omega = 2\;\pi\;\text{rev}^{-1}\times 2\;\text{rev}\cdot\text{s}^{-1} = 4 \pi \;\text{s}^{-1}$ .

Maximum emf in the coil:

$\epsilon_\text{max} = \omega\cdot\phi_\text{max} = 4\;\pi \times 7.2\;\text{Wb} = 90\;\text{V}$ .

Emf varies over time. The trend of change in emf over time resembles the shape of either a sine wave or a cosine wave since the coil rotates at a constant angular speed. The question states that emf is "zero at t = 0." As a result, a sine wave will be the most appropriate here since $\sin{0} = 0$ .

$\displaystyle \epsilon(t) = \epsilon_\text{max}\cdot \sin{(\omega\cdot t)}$ .

Make sure that your calculator is in the radian mode.

$\displaystyle \epsilon\left(\frac{\pi}{32}\right) = 90\;\text{V}\times \sin\left(4\;\pi\times \frac{\pi}{32}\right) = 85\;\text{V}$ .

Consider the shape of a sine wave. The value of $\displaystyle \sin\left(\omega \cdot t\right)$ varies between -1 and 1 as the value of $t$ changes. The value of $\epsilon$ at time $t$ depends on the value of $\sin(\omega \cdot t)$ .