Answer:
2.5 kilograms = 2500 grams
Answer:
D = 30.625 m
Explanation:
given,
Speed of the climber = 1.3 m/s
time = 2.5 s
acceleration due to gravity = 9.8 m/s²
initial speed of the kit = 1.3 m/s
velocity of the kit after 2.5 s
using equation of motion
v = u + a t
v = 1.3 + 9.8 x 2.5
v = 25.8 m/s
distance travel by the kit in 2.5 s
v² = u² + 2 g h
25.8² = 1.3² + 2 x 9.8 x h
19.6 h = 663.95
h = 33.875 m
distance travel by the rock climber in 2.5 s
distance = speed of climber x time
h' = 1.3 x 2.5
h' = 3.25 m
Distance between kit and rock climber
D = h - h'
D = 33.875 - 3.25
D = 30.625 m
The kit is 30.625 m below climber.
The change in energy after the collision is <u>0.5</u>
<u />
<h3>What is change in energy?</h3>
This refers to the difference in the energy where energy is the capacity to do work. There different forms of energy they include mechanical energy, solar energy, electrical energy and so on.
The energy described in the problem is mechanical energy and it is of two types kinetic energy and potential energy
<h3>solving for the change in energy as a result of the collision</h3>
where mass of particle mp = 4 kg
mass of object mb = 6 kg
force constant of spring k = 100 N/m
amplitude A = 2 m
kinetic energy = 1/2 mv^2
initial velocity u = Aω
ω = sqrt ( 100/ 4 )
u = 2 sqrt ( 100/ 4 )
u = 10m/s
final velocity v = 5 m/s
change in energy
= - 0.5 * ( 4 + 4 ) * 5^2 + 0.5 * 4 * 10^2 ) / 0.5 * 4 * 10^2
= 0.5
Read more on change in energy here: brainly.com/question/26066414
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Answer:
670400 J
Explanation:
m = mass of water = 2 kg
T₀ = initial temperature of water = 20 ºC
T = initial temperature of water = 100 ºC
c = heat capacity of water = 4190 J /kg ºC
Q = energy needed to raise the temperature of water
Energy needed to raise the temperature of water is given as
Q = m c (T - T₀)
Inserting the values
Q = (2) (4190) (100 - 20)
Q = 670400 J
Answer:
1200.0 MilliAmps
Explanation is because you multiply it by 10
