All categories

3 years ago

Which of the following will decrease the frequency of collisions?

Chemistry

1 answer:

kogti [31]3 years ago

8 0

Answer:

The question isn't worded properly, but if 1 or 2 are DECREASED, the frequency of collisions of specified molecules will decrease.

Explanation:

Catalysts only facilitate reaction once molecules collide. Increased temperature makes molecules move more, and thus collide more. For concentration, if there are more molecules in the same amount of room/liquid, there will be more collisions because there are more of the molecules to collide.

You might be interested in

Identify the missing reagents 1 & 2; draw the final organic product(s)<br> c.

abruzzese [7]

Co2 is correct buddy

3 0

3 years ago

Calculate the mass of beryllium (Be) needed to completely react with 18.9 g nitrogen gas (N2) to produce Bez N2, which is the on

choli [55]

Answer:

C = 18.29 g

Explanation:

Given data:

Mass of beryllium needed = ?

Mass of nitrogen = 18.9 g

Solution:

Chemical equation:

3Be + N₂ → Be₃N₂

now we will calculate the number of moles of nitrogen:

Number of moles = mass/molar mass

Number of moles = 18.9 g/ 28 g/mol

Number of moles = 0.675 mol

Now we will compare the moles of nitrogen and Be from balance chemical equation.

N₂ : Be

1 : 3

0.675 : 3/1×0.675 = 2.03 mol

Number of moles of Be needed are 2.03 mol.

Mass of Beryllium:

Mass = number of moles × molar mass

Mass = 2.03 mol × 9.01 g/mol

Mass = 18.29 g

4 0

2 years ago

PLS I NEED HELP give me examples of an atom

Ugo [173]

Answer:

Neon (Ne)

Hydrogen (H)

Argon (Ar)

Iron (Fe)

Calcium (Ca)

Deuterium, an isotope of hydrogen that has one proton and one neutron.

Plutonium (Pu)

F-, a fluorine anion.

Explanation:

I got u

4 0

2 years ago

How many moles of Carbon are in 3.06 g of Carbon

natta225 [31]

Answer:

$\boxed {\boxed {\sf 0.255 \ mol \ C }}$

Explanation:

If we want to convert from grams to moles, the molar mass is used. This is the mass of 1 mole. They are found on the Periodic Table as the atomic masses, but the units are grams per mole (g/mol) instead of atomic mass units (amu).

Look up the molar mass of carbon.

Carbon (C): 12.011 g/mol

Set up a ratio using the molar mass.

$\frac {12.011 \ g \ C}{ 1 \ mol \ C}$

Since we are converting 3.06 grams to moles, we multiply by that value.

$3.06 \ g \ C*\frac {12.011 \ g \ C}{ 1 \ mol \ C}$

Flip the ratio. This way, the ratio is still equivalent, but the units of grams of carbon cancel.

$3.06 \ g \ C* \frac{1 \ mol \ C}{12.011 \ g\ C}$

$3.06 * \frac{1 \ mol \ C}{12.011 }$

$\frac {3.06}{12.011 } \ mol \ C$

$0.25476646 \ mol \ C$

The original measurement of grams (3.06) has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.

0.25476646

The 7 in the ten-thousandth place tells us to round the 4 up to a 5.

$0.255 \ mol \ C$

3.06 grams of carbon is approximately <u>0.255 moles of carbon.</u>

3 0

2 years ago

Carbon dioxide and ____ are outputs of cellular respiration

vova2212 [387]

Answer:

oxygen

Explanation:

plants use oxygen

5 0

2 years ago