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vfiekz [6]
3 years ago
11

Find the Volume of a cylinder with a base area of 25pi inches squared, and height equal to the radius

Mathematics
1 answer:
Flauer [41]3 years ago
6 0
The answer is 981.75
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Y=(1/2)^x +2. What is the horizontal asymptote of this function?
professor190 [17]
\lim_{x\to -\infty} \left(\frac{1}{2}\right)^x+2=\infty+2=\infty\\
\lim_{x\to \infty} \left(\frac{1}{2}\right)^x+2=0+2=2\\

There is one-sided horizontal asymptote y=2
6 0
4 years ago
-3j - (-4) over -6 = 12 j= ? ​
babymother [125]

Answer:

j =76/3

Step-by-step explanation:

-3j -  -4

------------------ = 12

-6

Multiply each side by -6 to clear the fraction

-3j +4

------------------ * -6 = 12 *-6

-6

-3j +4 = -72

Subtract 4 from each side

-3j +4-4 = -72 -4

-3j = -76

Divide each side by -3

-3j/-3 = -76/-3

j = 76/3

5 0
4 years ago
HELP HELP PLEASE ASAP
topjm [15]

Answer:

Cost for skii: J(x) = 30x + 7

Cost for beach chair: B(x) = 5x + 3

=> Total cost = J(x) + B(x) = 30x + 7 + 5x + 3 = 35x + 10

=> Option C is correct.

Hope this helps!

:)

7 0
3 years ago
Need help asap!!!!!!!!!!!!!!!!!!!
ololo11 [35]
Okay so this is how I got the answer.... I didn’t lol
4 0
3 years ago
12x - 2y = -1<br>+ 4x + 6y= -4<br>​
svp [43]

Answer:

x = -7/40 , y = -11/20

Step-by-step explanation:

Solve the following system:

{12 x - 2 y = -1 | (equation 1)

4 x + 6 y = -4 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{12 x - 2 y = -1 | (equation 1)

0 x+(20 y)/3 = (-11)/3 | (equation 2)

Multiply equation 2 by 3:

{12 x - 2 y = -1 | (equation 1)

0 x+20 y = -11 | (equation 2)

Divide equation 2 by 20:

{12 x - 2 y = -1 | (equation 1)

0 x+y = (-11)/20 | (equation 2)

Add 2 × (equation 2) to equation 1:

{12 x+0 y = (-21)/10 | (equation 1)

0 x+y = -11/20 | (equation 2)

Divide equation 1 by 12:

{x+0 y = (-7)/40 | (equation 1)

0 x+y = -11/20 | (equation 2)

Collect results:

Answer:  {x = -7/40 , y = -11/20

6 0
3 years ago
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