Given :
- A = {x: 2x² + 3x - 2 = 0 }
- B = {x : x² + 3x - 4 = 0 }
To find :
Solution :-
<u>The </u><u>first </u><u>set </u><u>is </u><u>,</u>
- A ={x : 2x² + 3x - 2 = 0}
<u>Solving</u><u> </u><u>the </u><u>Quadratic</u><u> equation</u><u> </u><u>,</u>
- 2x² + 3x - 2 = 0
- 2x² + 4x - x - 2 = 0
- 2x( x + 2) -1( x + 2 ) = 0
- (2x -1) ( x + 2) = 0
- x = 0.5 , -2
<u>Hence</u><u> </u><u>,</u>
<u>The </u><u>second</u><u> </u><u>set </u><u>is </u><u>,</u>
- B ={ x :x² + 3x - 4 = 0 }
<u>Solving</u><u> the</u><u> Quadratic</u><u> equation</u><u> </u><u>,</u>
- x² + 3x - 4 = 0
- x² + 4x - x - 4 = 0
- x( x + 4)-1 ( x +4) = 0
- (x + 4) ( x -1) = 0
- x = 1 , -4
<u>Hence</u><u> </u><u>,</u>
<u>Now </u><u>,</u>
- A U B = { 0.5 , 1 , 4 , -2}
- A Π B = {∅ }
Since AΠ B is a null set , hence ,
-2x + 4.4 = 23.8
Subtract 4.4 from both sides
-2x = 19.4
Divide both sides by-2:
X = -9.7
Answer: C. -9.7
The answer would be x ≠ 0
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First start with the left side, doing distributive property
So... -2(x) = -2x and -2(5) = -10 Therefore on the left side you now have -2x -10
Next do the same on the right side
-2(x) = - 2x and -2(-2) = 4 so you have -2x + 4 + 5 and you add 4 and 5, leaving you with -2x + 9
Now that you have simplified both sides the problem now looks like this:
-2x - 10 = -2x + 9
Because you have equal terms on both sides (-2) those cancel out so you have -10 = 9
Just from looking at this we know that the statement is false because -1o does not equal 9
*The symbol, "≠" means not equal to"
4.3 I believe. That's the answer I got.
Answer:
the answer to the question is y=x+2.
