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4 years ago

5x-6y+87z=6x+96y-867z

Mathematics

1 answer:

sasho [114]4 years ago

3 0

Answer:

The given equation cannot be solve but can be simplified.

Step-by-step explanation:

Given equation: 5x-6y+87z = 6x+96y-867z

We can only simplify the equation, but we cannot solve because there are three unknown variables and only one equation.

To successfully solve, we requires minimum of three equations.

lets simplify it:

first place the similar variables at one place:

5x - 6x -6y - 96y +87z +867z =0

Now perform the respective operation to the constants:

-x-102y+ 953z =0

⇒ x +102y + 953z =0

Which is the required simplification.

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sattari [20]

Step-by-step explanation:

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3 years ago

colleen rolls a number cube and flips a coin. What is the probabilty that she will roll at least a 3 or flip heads

anyanavicka [17]

The probability of her rolling at least a 3 and flipping heads is 4/12 or 33 1/3 %.

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I hope this helps!!

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3 years ago

Oscar is washing cars to earn extra money.Goal is to wash 45 cars. he can wash 5 cars per day. Which equation can he use to find

Rama09 [41]

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3 years ago

About 10% of people in the United States are left handed. Suppose we take a sample of 120 U.S. Residents, and let X = the number

olganol [36]

Answer:

1) $E(X) = np = 120*0.1 =12$

$SD(X) = \sqrt{np(1-p)}= \sqrt{120*0.1*(1-0.1)} =3.286$

For this case we can interpret that the expected variation around the mean is about 3.3 people approximated

2) $P(X\geq 16)$

And we can use the normal approximation given by:

$X \sim N(12, \sigma =3.286)$

And we can use the z score formula given by:

$z = \frac{X -\mu}{\sigma}$

And if we find the z score for 16 we got:

$z = \frac{16-12}{3.286}= 1.217$

And we can find this probability using the normal standard distribution or excel and we got:

$P(Z>1.217) = 0.112$

3) For this case we can conclude that the probability to find 16 or more individuals left handed in a sample of 120 is about 0.112 or 11.2%

Step-by-step explanation:

Let X represent the random variable for the number of residents who are left handed

And for this case we can model this variable with this distirbution:

$X\sim Binom(n= 120 , p =0.1)$

Part 1

The mean is given by:

$E(X) = np = 120*0.1 =12$

And the deviation would be:

$SD(X) = \sqrt{np(1-p)}= \sqrt{120*0.1*(1-0.1)} =3.286$

For this case we can interpret that the expected variation around the mean is about 3.3 people approximated

Part 2

We want to calculate this probability:

$P(X\geq 16)$

And we can use the normal approximation given by:

$X \sim N(12, \sigma =3.286)$

And we can use the z score formula given by:

$z = \frac{X -\mu}{\sigma}$

And if we find the z score for 16 we got:

$z = \frac{16-12}{3.286}= 1.217$

And we can find this probability using the normal standard distribution or excel and we got:

$P(Z>1.217) = 0.112$

Part 3

For this case we can conclude that the probability to find 16 or more individuals left handed in a sample of 120 is about 0.112 or 11.2%

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3 years ago

What is a undo table in math

jenyasd209 [6]

<span>An "undo" table just reverses the ORDER of the steps, doing the OPPOSITE operation as you go. </span>

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4 years ago