Ask question

Ask question

All categories

Murljashka [212]

4 years ago

12

Please help me out please

1 answer:

IgorLugansk [536]4 years ago

7 0

Answer:

h=20

Step-by-step explanation:

h=3 (V/lw)

h= 3 (960/12*12)

You might be interested in

Which of the choice below follows exponential pattern

blsea [12.9K]

Answer:

Step-by-step explanation:

7 0

3 years ago

Find the value(s) of k such that 4x² + kx + 4 = 0 has 1 rational solution

Blababa [14]

Answer:

If you mean only one rational solution, the answer is

$k_1 = 8, k_2 = -8$

If you mean at least 1 rational solution, the answer is

$k\in (-\infty, -8]\cup[8, \infty)$

Step-by-step explanation:

$4x^2 + kx + 4 = 0$

Let's calculate the discriminant.

$\Delta = b^2 - 4ac$

$\Delta = k^2 -4 \cdot 4 \cdot 4$

$\Delta = k^2 -64$

Now, remember that:

$\text{If } \Delta > 0 : \text{2 Real solutions}$

$\text{If } \Delta = 0 : \text{1 Real solution}$

$\text{If } \Delta < 0 : \text{No Real solution}$

Therefore, I will just consider the first two cases.

$k^2 - 64 > 0$

and

$k^2 -64 = 0$

$\boxed{\text{For } k^2 - 64 > 0}$

$k^2 > 64 \Longleftrightarrow k>\pm\sqrt{64} \Longleftrightarrow k\in (-\infty, -8)\cup(8, \infty)$

$\boxed{\text{For } k^2 - 64 = 0}$

$k^2 = 64 \Longleftrightarrow k=\pm\sqrt{64} \implies k_1 = 8, k_2 = -8$

7 0

3 years ago

What is the slope of the line shown below

Aleksandr-060686 [28]

the answer is C. 7/3

5 0

3 years ago

Point t bisects line uv. Find uv if ut=2 7/8

weqwewe [10]

$If\ T\ bisects\ \overline{UV}\ then\ |UT|=|VT|\ and\ |UT|+|VT|=|UV|.\\\\|UT|=2\frac{7}{8}\to|VT|=2\frac{7}{8}\\\\|UV|=2\frac{7}{8}+2\frac{7}{8}=4\frac{14}{8}=4\frac{7}{4}=5\frac{3}{4}\\\\Answer:\boxed{|UV|=5\frac{3}{4}}$

6 0

4 years ago

Read 2 more answers

What us the equation of the line that has a slope of 0 and passes though the point (4,22)

Brums [2.3K]

Point-slope form: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)

Data:
(4,22)
m=0

y-22=0(x-4)
y-22=0
y=22 (slope intercept form)

Answer: the line will be: y=22

7 0

4 years ago