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Thepotemich [5.8K]

2 years ago

6

What is the equation of the line that passes through (–2, –3) and is perpendicular to 2x – 3y = 6?

1 answer:

lyudmila [28]2 years ago

6 0

<span>An equation that would be perpendicular is opposite the reciprocal. </span>

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5 times 2/12=___ 4 times 2/3=___ 6 times 2/6=___ 2 times 4/8=___ 3 times 1/2=____

uysha [10]

Answer:

1) .8333 2) 2.6666 3) 2 4) 1.5

Step-by-step explanation:

I just used a calculator.

3 0

3 years ago

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Frank devised a formula for his catering business that calculates the number of meatballs he needs to prepare. The formula is m=

NeX [460]

So if m=4a+2c is your equation then all you have to do is plug in the numbers.

So you then get m=4(25)+2(7), for 25 adults and 7 children.

Then you solve. m=100+2(7)
m=100+14
m=114
So Frank will need 114 Meatballs for the party of 25 adults and 7 children
Hope this helps! And if you need anything else just ask :)

5 0

3 years ago

Which one<br> also whats 473+838=

Mashutka [201]

Answer:

1,311

Step-by-step explanation:

7 0

3 years ago

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Students are given 3 minutes to complete each multiple-choice question on a test and 8 minutes for each free-response question.

kakasveta [241]

Answer:

It would be 8(15-m)

4 0

3 years ago

Which expression is equivalent to 4√24x∧6y÷ 128x∧4y∧5

LenKa [72]

Answer:

Option D. $\sqrt[4]{\frac{3x^{2}}{2y}}$

Step-by-step explanation:

$\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}}$

$\sqrt[4]{(\frac{24}{128})\times (\frac{x^{6}}{x^{4}})\times (\frac{y}{y^{5}})}$

= $\sqrt[4]{(\frac{3}{16})\times {(x)^{6-4}}\times{(y)^{1-5}}}$

= $\sqrt[4]{(\frac{3}{16})\times x^{2}y^{-4}}$

= $\sqrt[4]{\frac{3}{(2)^{4}}\times x\times y^{-4}}$

= $\sqrt[4]{(3\times x^{2)\times (\frac{y^{-1}}{2})^{4}}}$

= $\frac{y^{-1}}{2}\sqrt[4]{3x^{2}}$

= $\sqrt[4]{\frac{3x^{2}}{2y}}$

Option D. $\sqrt[4]{\frac{3x^{2}}{2y}}$ is the correct answer.

5 0

3 years ago