Answer:
<u>The two numbers are 23 and 56</u>
Step-by-step explanation:
Let's say the two numbers are A and B.
We are told:
1) A+B=79
2) 3A+5B=283
Let's take the first expression and solve for A:
A+B=79
A=79-B
Now use this value of A in the second expression:
3A+5B=283
3(79-B)+5B=283
237-3B+5B=283
2B = 46
B = 23
Since B=23, we know from 1) that
A+B=79
A+23=79
A = 56
<u>CHECK:</u>
Does A+B=79?
56+23 = 79? <u>YES</u>
Does 3A+5B=283?
3(56)+5(23)=283
168 + 115 = 283? <u>YES</u>
-3y +4 = -11
-4 -4
-3y = -15
—— —-
-3y -3y
Y= 5
Answer:
Step-by-step explanation:
Assuming Roberto wants to completely fill each page that he puts cards in, this function describes the number of 2-card pages, a, and 3-card pages, b.
2a + 3b =18
Ricardo can fill up 9 2-card pages, and 6 3-card pages.
a=9, b=0
We must add 2 3-card pages at a time,so that we have an even number for the 2-card pages:
a=6, b=2
Add 2 to b once more:
a=3, b=4
One more time:
a=0, b=6:
Thus, Ricardo can display his figures in the following page combinations:
a=9, b=0
a=6, b=2
a=3, b=4
a=0, b=6
Remember that a= number of 2-card pages and b=number of 3-card pages
There are 4 different ways that Ricardo can arrange his figures in terms of what kind of pages he uses.
Answer:
Because 0 counts as the first possible number. 0-9 gives you 10 possible numbers.
Step-by-step explanation:
