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3 years ago

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345 in standard form

1 answer:

steposvetlana [31]3 years ago

5 0

345 in Standard Form is 3.45 x 10^2

This is because when in standard form the decimal should move to the right 2 times.

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Which expression represents the phrase "twice the sum of a number and three"?

exis [7]

2(n+3)
two times the sum of a number (n) and 3

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3 years ago

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Miles buys a 10-ounce bag of chips. He weighs it in a scale and makes four measurements. Which measurement is the most accurate

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I believe it's A(that would be the closest to 10oz)

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WILL GIVE BRAINLEST ANSWER IF ANSWERED IN THE NEXT 24 HRS Express the complex number in trigonometric form. -5i

trasher [3.6K]

Answer:

$z=5\left(\cos \left(\dfrac{3\pi}{2}\right)+i\sin \left(\dfrac{3\pi}{2}\right)\right)$

Step-by-step explanation:

If a complex number is z=a+ib, then the trigonometric form of complex number is

$z=r(\cos \theta +i\sin \theta)$

where, $r=\sqrt{a^2+b^2}$ and $\tan \theta=\dfrac{b}{a}$ , $\theta$ is called the argument of z, $0\leq \theta\leq 2\pi$ .

The given complex number is -5i.

It can be rewritten as

$z=0-5i$

Here, a=0 and b=-5. $\theta$ lies in 4th quadrant.

$r=\sqrt{0^2+(-5)^2}=5$

$\tan \theta=\dfrac{-5}{0}$

$\tan \theta=\infty$

$\theta=2\pi -\dfrac{\pi}{2}$ $[\because \text{In 4th quadrant }\theta=2\pi-\theta]$

$\theta=\dfrac{3\pi}{2}$

So, the trigonometric form is

$z=5\left(\cos \left(\dfrac{3\pi}{2}\right)+i\sin \left(\dfrac{3\pi}{2}\right)\right)$

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3 years ago

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Suppose that $3000 is placed in an account that pays 16% interest compounded each year. Assume that no withdrawals are made from

Papessa [141]

Answer:

a) $3480

b) $4036.8

Step-by-step explanation:

The compound interest formula is given by:

$A(t) = P(1 + \frac{r}{n})^{nt}$

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

Suppose that $3000 is placed in an account that pays 16% interest compounded each year.

This means, respectively, that $P = 3000, r = 0.16, n = 1$

So

$A(t) = P(1 + \frac{r}{n})^{nt}$

$A(t) = 3000(1 + \frac{0.16}{1})^{t}$

$A(t) = 3000(1.16)^{t}$

(a) Find the amount in the account at the end of 1 year.

This is A(1).

$A(t) = 3000(1.16)^{t}$

$A(1) = 3000(1.16)^{1} = 3480$

(b) Find the amount in the account at the end of 2 years.

This is A(2).

$A(2) = 3000(1.16)^{2} = 4036.8$

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3 years ago

6x-12y=36 <br> Converting from standard form to slope intercept form

AnnyKZ [126]

Slope intercept form is y=mx+b
6x-12y=36
-12y=36-6x
y=36-6x/-12

y=0.5x-3

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3 years ago

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