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anygoal [31]
3 years ago
12

345 in standard form

Mathematics
1 answer:
steposvetlana [31]3 years ago
5 0
345 in Standard Form is 3.45 x 10^2

This is because when in standard form the decimal should move to the right 2 times.
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Which expression represents the phrase "twice the sum of a number and three"?
exis [7]
2(n+3)
two times the sum of a number (n) and 3
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3 years ago
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Miles buys a 10-ounce bag of chips. He weighs it in a scale and makes four measurements. Which measurement is the most accurate
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I believe it's A(that would be the closest to 10oz)
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WILL GIVE BRAINLEST ANSWER IF ANSWERED IN THE NEXT 24 HRS Express the complex number in trigonometric form. -5i
trasher [3.6K]

Answer:

z=5\left(\cos \left(\dfrac{3\pi}{2}\right)+i\sin \left(\dfrac{3\pi}{2}\right)\right)

Step-by-step explanation:

If a complex number is z=a+ib, then the trigonometric form of complex number is

z=r(\cos \theta +i\sin \theta)

where, r=\sqrt{a^2+b^2} and \tan \theta=\dfrac{b}{a}, \theta is called the argument of z, 0\leq \theta\leq 2\pi.

The given complex number is -5i.

It can be rewritten as

z=0-5i

Here, a=0 and b=-5. \theta lies in 4th quadrant.

r=\sqrt{0^2+(-5)^2}=5

\tan \theta=\dfrac{-5}{0}

\tan \theta=\infty

\theta=2\pi -\dfrac{\pi}{2}    [\because \text{In 4th quadrant }\theta=2\pi-\theta]

\theta=\dfrac{3\pi}{2}

So, the trigonometric form is

z=5\left(\cos \left(\dfrac{3\pi}{2}\right)+i\sin \left(\dfrac{3\pi}{2}\right)\right)

4 0
3 years ago
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Suppose that $3000 is placed in an account that pays 16% interest compounded each year. Assume that no withdrawals are made from
Papessa [141]

Answer:

a) $3480

b) $4036.8

Step-by-step explanation:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

Suppose that $3000 is placed in an account that pays 16% interest compounded each year.

This means, respectively, that P = 3000, r = 0.16, n = 1

So

A(t) = P(1 + \frac{r}{n})^{nt}

A(t) = 3000(1 + \frac{0.16}{1})^{t}

A(t) = 3000(1.16)^{t}

(a) Find the amount in the account at the end of 1 year.

This is A(1).

A(t) = 3000(1.16)^{t}

A(1) = 3000(1.16)^{1} = 3480

(b) Find the amount in the account at the end of 2 years.

This is A(2).

A(2) = 3000(1.16)^{2} = 4036.8

4 0
3 years ago
6x-12y=36 <br> Converting from standard form to slope intercept form
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Slope intercept form is y=mx+b
6x-12y=36
-12y=36-6x
y=36-6x/-12

y=0.5x-3
5 0
3 years ago
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