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Korolek [52]
3 years ago
14

An fm radio station broadcasts at a frequency of 91 mhz . part a what inductance should be paired with a 9.0 pf capacitor to bui

ld a receiver circuit for this station?
Physics
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0
It's not clear exactly how you intend to use an ' L ' and a ' C ' in a
receiver circuit.

Perhaps you just want a simple resonant 'tank', so that the voltage
across it peaks at 91 MHz. Then you just want to know what parallel
L-C is resonant at 91 MHz.

Without resistance to complicate things, the resonant frequency
of a parallel L-C is

f = 1 / [ 2π √(LC) ].

Before we get tangled up in this thing,
let's just solve it for ' L ' :
Multiply each side by √(LC), then divide each side by f ,
and then it says

√(LC) = 1 / (2π f)

Divide each side by √C :

√L = 1 / 2πf√C

then square each side:

L = 1 / (4 · π² · f² · C)

and now we can easily go ahead and find ' L '.

L = 1 / (4 · π² · 91² · 10¹² · 9 · 10⁻¹²)

When I stuff that through my calculator, I get

L = 0.34 microhenry
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3 years ago
A scientist fixes a test charge q′ to point P and then measures the electrostatic force it experiences there. She then calculate
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Answer:

<em>Correct answer: B.</em>

Explanation:

Electrostatic Field

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\displaystyle E=\frac{F}{q'}

The electrostatic force between two point charges is

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\displaystyle E=\frac{\frac{k\ q_1\ q'}{r^2}}{q'}

\displaystyle E=\frac{k\ q_1}{r^2}

The theory shows that the electric field doesn't depend on the test charge used, i.e., if we now use q'=-q', the electric force will be of the same magnitude but in the opposite direction, thus the electric field will be the same. Let's recall the formula is used to compute the scalar value of the field, the direction must be studied separately.

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\displaystyle E=\frac{k\ q_1}{r^2}

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Correct answer: B.

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