Answer:
Direct proportionality
Explanation:
The graph of variables that are directly proportional such as the temperature and volume of a gas has a graph consisting of a diagonal line that from the lower left of the graph to the upper right of the graph
According to Charles law, the volume of a given mass of gas is directly proportional to its temperature in Kelvin at constant pressure
Charles law can be represented mathematically as V ∝ T
From which we have;
V₁/T₁ = V₂/T₂, therefore, the graph of V to T has a constant slope, ΔV/ΔT.
The rocky object orbiting in space is most likely referred to as an asteroid.
<h3>What is an Asteroid?</h3>
This is referred to a rocky object which revolve around the sun and are considered too small to be called a planet.
Asteroids was observed with the use of a telescope and is around 250 km wide thereby making it the most appropriate choice.
Read more about Asteroids here brainly.com/question/11996385
<u>100° C</u> she can expect once the water begins to boil.
<u>Option: B</u>
<u>Explanation:</u>
The boiling point for water at 1 pressure atmosphere of sea level is 212 ° F or 100 ° C. That value isn't a fixed. Water's boiling point is dependent on the ambient pressure, which varies based on elevation. At a lower temperature, water boils as one gains altitude like getting higher on a hill, and boils at a higher temperature if one increases the atmospheric pressure of returning to or below sea level.
It also relies upon the water's purity. Water containing contaminants like salted water boils at a level higher than pure water. This effect is called acceleration of the boiling point and is one of the material's colligative features.
Answer:
Proof in explanataion
Explanation:
The basic dimensions are as follows:
MASS = M
LENGTH = L
TIME = T
i)
Given equation is:
where,
H = height (meters)
u = speed (m/s)
g = acceleration due to gravity (m/s²)
Sin Ф = constant (no unit)
So there dimensions will be:
H = [L]
u = [LT⁻¹]
g = [LT⁻²]
Sin Ф = no dimension
Therefore,
![[L] = \frac{[LT^{-1}]^2}{[LT^{-2}]}\\\\\ [L] = [L^{(2-1)}T^{(-2+2)}]](https://tex.z-dn.net/?f=%5BL%5D%20%3D%20%5Cfrac%7B%5BLT%5E%7B-1%7D%5D%5E2%7D%7B%5BLT%5E%7B-2%7D%5D%7D%5C%5C%5C%5C%5C%20%5BL%5D%20%3D%20%5BL%5E%7B%282-1%29%7DT%5E%7B%28-2%2B2%29%7D%5D)
<u>[L] = [L]</u>
Hence, the equation is proven to be homogenous.
ii)
where,
F = Force = Newton = kg.m/s² = [MLT⁻²]
G = Gravitational Constant = N.m²/kg² = (kg.m/s²)m²/kg² = m³/kg.s²
G = [M⁻¹L³T⁻²]
m₁ = m₂ = mass = kg = [M]
r = distance = m = [L]
Therefore,
![[MLT^{-2}] = \frac{[M^{-1}L^{3}T^{-2}][M][M]}{[L]^2}\\\\\ [MLT^{-2}] = [M^{(-1+1+1)}L^{(3-2)}T^{-2}]\\\\](https://tex.z-dn.net/?f=%5BMLT%5E%7B-2%7D%5D%20%3D%20%5Cfrac%7B%5BM%5E%7B-1%7DL%5E%7B3%7DT%5E%7B-2%7D%5D%5BM%5D%5BM%5D%7D%7B%5BL%5D%5E2%7D%5C%5C%5C%5C%5C%20%5BMLT%5E%7B-2%7D%5D%20%3D%20%5BM%5E%7B%28-1%2B1%2B1%29%7DL%5E%7B%283-2%29%7DT%5E%7B-2%7D%5D%5C%5C%5C%5C)
<u>[MLT⁻²] = [MLT⁻²]</u>
Hence, the equation is proven to be homogenous.
