Answer:
magnitude = 3
unit vector = 
Explanation:
Given vectors:
u = 2i + 2j - k
v = -i + k = -i + 0j + k
(a) u x v is the cross product of u and v, and is given by;
u x v = i(2+0) - j(2 - 1) + k(0 - 2)
u x v = 2i - j - 2k
Now the magnitude of u x v is calculated as follows:
| u x v | = 
| u x v | = 
| u x v | = 
| u x v | = 3
Therefore, the magnitude of u x v is 3
(b) The unit vector û parallel to u x v in the direction of u x v is given by the ratio of u x v and the magnitude of u x v. i.e
û =
u x v = 2i - j - 2k [<em>calculated in (a) above</em>]
|u x v| = 3 [<em>calculated in (a) above</em>]
∴ û = 
∴ û = 
Answer:
1. Nismo: 
2. Ferdinand:
, Shelby: 
3. Enzo: 
4. Lotus: 
Explanation:
The luminosity of a star is the amount of light it emits from its surface. The luminosity is an intrinsic property of the star. Apparent brightness is how bright the star appears to a detector on Earth. Apparent brightness is not an intrinsic property of the star; it depends on the location of the observer.
As light travels towards an observer, it spreads out and covers a larger area, reducing the intensity. Thus the apparent brightness is inversely proportionate to the square of the distance between the star and observer.
Apparent brightness can be calculated by the formula below:

Where,
is apparent brightness,
is luminosity,
is the distance between the star and observer
Enzo: 200 LSun , 20 ly



Ferdinand: 400 LSun , 20 ly



Nismo: 100 LSun , 8 ly



Lotus: 400 LSun , 40 ly



Shelby: 100 LSun , 10 ly



Apparent brightness of stars is summarized as below. Absolute values are considered as units are unspecified
Enzo: 
Ferdinand: 
Nismo: 
Lotus: 
Shelby: 
Organized in order of apparent brightness
1. Nismo: 
2. Ferdinand:
, Shelby: 
3. Enzo: 
4. Lotus: 
Answer:
acceleration is 1.59 m/s²
required % is 16.22 %
Explanation:
given data
radius = 63 m
speed = 10 m/s
to find out
acceleration of the car and acceleration due to gravity
solution
we know car is moving in circular path
so acceleration will be, a =
.........1
put here value
a =
a = 1.59 m/s²
so acceleration is 1.59 m/s²
so acceleration due to gravity as a percentage is 9.8 m/s²
required % = 
required % = 16.22 %
V = f x lamda
Wave speed = frequency x wavelength
2x1 = 2 so wave speed = 2m/s
Let me know if you have any questions