______ is the percent ionization of a weak acid in water increases as the concentration of acid decreases.

1 answer:

7 0

The ratio of concentration of ionized acid to the initial concentration of acid multiplied by 100 will give the percent ionization of a weak acid in water increases as the concentration of acid decreases.

Explanation:

Percent ionization is used for quantifying the number of ions present in the weak acid when dissolved in a solution. So it is similar to the pKa value. The percent ionization value can be determined as negative log of dissociation constant. Also the as the number of ions increases in weak acid, the concentration of acid will be decreasing . It can be calculated using the formula for percent ionization as follows:

$Percent ionization = \frac{Ionized acid concentration}{Initial concentration of acid} * 100$

As the water volume or concentration increases, the acid will get diluted much more thus leading to decrease in the concentration of acid.

So the ratio of concentration of ionized acid to the initial concentration of acid multiplied by 100 will give the percent ionization of a weak acid in water increases as the concentration of acid decreases.

You might be interested in

A student examines the effect of the number of D batteries in a closed circuit on the brightness of a light bulb. In the experim

salantis [7]

The correct answer is the Type of batteries

Explanation:

In an experiment, it is normal the researcher modifies one variable, in this case, the number of batteries (independent variable), and this variable affects the variable tested, in this case, the brightness of the bulb (dependent variable).

However, other factors or variables should be constant to guarantee the results are reliable. In this context, one factor that the student should keep constant is the type of batteries he uses because this is not one of the main variables and therefore it is not expected he changes this on purpose or this is affected by other variables. Moreover, by making any change the experiment can be negatively affected. For example, batteries might differ in their power capacity this can affect the brightness of the bulbs.

3 0

3 years ago

Which region is also the spinal column region? vertebral scapular pelvic sternal

NNADVOKAT [17]

Vertebral ...............

6 0

3 years ago

Read 2 more answers

The image shows a magnetic field around the poles of a magnet. Identify the areas where the magnetic force is the strongest.

valentinak56 [21]

The magnetic field is strongest immediately adjacent to the poles.

I know this from previous experience, NOT from the image, since you neglected to show us the image. That makes it tough for a lot of people.

3 0

3 years ago

A small block of wood of inertia mb is released from rest a distance h above the ground, directly above your head. you decide to

Zinaida [17]

Since I'm assuming that its perfectly elastic, considering there's not enough information given, so I think that no energy is dissipated in the collision

hmax = h - d + { [ mpvp - mb√(2gd) ] / (mp+mb) }² / (2g)

7 0

3 years ago

Two light bulbs of resistance R1 and R2 (R2 > R1) and a battery are all connected in series. (a) Which bulb is brighter? (b)

mr Goodwill [35]

Answer:

(a) higher resistance bulb in series

(b) The bulb which has lower resistance should bright more as there is more flow of current in it while connected in parallel.

Explanation:

If the light bulbs are in series, each will have the same current. The power dissipated by the bulb as heat and light is given by P=I^2*R. Thus the bulb with the higher resistance will be brighter.

if the bulbs are in parallel, each will have the same voltage. The power dissipated by the bulb as heat and light is given by P=V^2*/R. Thus the bulb with the lower resistance will be brighter.

7 0

3 years ago