______ is the percent ionization of a weak acid in water increases as the concentration of acid decreases.
1 answer:
The ratio of concentration of ionized acid to the initial concentration of acid multiplied by 100 will give the percent ionization of a weak acid in water increases as the concentration of acid decreases.
Explanation:
Percent ionization is used for quantifying the number of ions present in the weak acid when dissolved in a solution. So it is similar to the pKa value. The percent ionization value can be determined as negative log of dissociation constant. Also the as the number of ions increases in weak acid, the concentration of acid will be decreasing . It can be calculated using the formula for percent ionization as follows:
As the water volume or concentration increases, the acid will get diluted much more thus leading to decrease in the concentration of acid.
So the ratio of concentration of ionized acid to the initial concentration of acid multiplied by 100 will give the percent ionization of a weak acid in water increases as the concentration of acid decreases.
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Answer:
The option (b) is correct.
Explanation:
The expression for the power in terms of work done is as follows;
Here, W is the work done, t is the time taken and P is the power.
According to the given problem, six identical resistors are connected in series with a battery. The number of joules per second supplied by the battery is then determined.
The expression for the equivalent resistance in the series combination is as follows;
R_{eq}=R_{1}+R_{2}......+R_{6}
Put R_{1},R_{2}......,R_{6}=R.
R_{eq}=R+R+R+R+R+R
R_{eq}=6R
It is given in the problem that a seventh resistor is added (in series).
R_{eq}=R_{1}+R_{2}......+R_{7}
Put R_{1},R_{2}......,R_{7}=R.
R_{eq}=R+R+R+R+R+R+R
R_{eq}=7R
The expression for the power in terms of voltage and resistance is as follows;
Here, R is the resistance.
From the above expression, it can be concluded that the power, the number of joules per second supplied by the battery is inversely proportional to the resistance. The equivalent resistance increases if the seventh resistance is connected with a battery.
If a seventh resistor is added (in series) the number of joules per second supplied by the battery decreases.
Therefore, the option (b) is correct.