Long wave I think is the correct answer
You don't have to worry about converting to moles and back to liters. You need to know about Gay-Lussac's law of combining volumes. Coupled with Avogadro's law which says that the moles of gas are proportional to the volume, all we have to do is:
2H2(g) + O2(g) -> 2H2O(g)
2L ..........1L ..........2L
7.25L .....3.63L .....7.25L
The only work is dividing 7.25 by 2.
Answer:
Mass of helium = 4426.9524 g
Mass of hydrogen gas = 2213.4762 g
Explanation:
Pressure = 135 atm
Temperature = 24 °C
Volume = 200 L
Number of moles = ?
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (24 + 273.15) K = 297.15 K
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
135 atm × 200 L = n × 0.0821 L.atm/K.mol × 297.15 K
⇒n = 1106.7381 moles
<u>For helium gas:</u>
Molar mass = 4 g/mol
The formula for the calculation of moles is shown below:
Thus,

<u>For hydrogen gas:</u>
Molar mass = 2 g/mol
The formula for the calculation of moles is shown below:
Thus,

Ka is the equilibrium constant for the ionization for a reaction. It is calculated as follows
ka is equal to (H3o ions)(A-) divided by (HA)
2.00x106i s equal to 0.153x0.153 divided by ( HA)
(2.00x106)HA is equal to 0.023409
HA concentration is therefore equal to 0.023409/2.00x106 which is 1.104x10^-4moles/litre