Physics !!!!!!!!!!!!!!
1 answer:
1) The impulse on the airplane is 720,000 kg m/s
2) The momentum of the cart is 15 kg m/s
3) The recoil velocity of the cannon is 1.4 m/s is the direction opposite to the clown
Explanation:
1)
The impulse exerted on an object is equal to the change in momentum of the object:
where
m is the mass of the object
v is the final velocity
u is the initial velocity
For the airplane in the problem:
m = 45,000 kg
u = 242 m/s
v = 258 m/s
So, the impulse is
2)
The momentum of an object is given by
where
m is the mass of the object
v is its velocity
In this problem, we have
m = 20 kg is the mass of the cart
v = 0.75 m/s is its velocity
Substituting,
3)
We can solve this problem by using the law of conservation of momentum: in fact, the total momentum of the cannon+clown system must be conserved before and after the shot.
Before the shot, the total momentum is zero, because they are both at rest:
while the total momentum after the shot is
where
m = 70 kg is the mass of the clown
v = 15 m/s is the velocity of the clown
M = 750 kg is the mass of the cannon
V is the recoil velocity of the cannon
Since the total momentum is conserved,
so we find:
Where the negative sign means the cannon moves in the direction opposite to the clown.
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The concept of conservation of energy and harmonic motion allows to find the result for the power where the kinetic and potential energy are equal is:
x = 0.135 cm
Given parameters
- The mass m = 220 g = 0.220 kg
- The spring cosntnate3 k = 7.0 N / m
- Initial displacement A = 5.2 cm = 5.2 10-2 m
To find
- The position where the kinetic and potential energy are equal
A simple harmonic movement is a movement where the restoring force is proportional to the displacement, the result of this movement is described by the expression.
x = A cos wt + fi
w² =
Where x is the displacement from the equilibrium position, A the initial amplitude of the system, w the angular velocity t the time, fi a phase constant determined by the initial conditions, k the spring constant and m the mass.
The speed is defined by the variation of the position with respect to time.
v =
let's evaluate
v = - A w sin (wt + Ф)
Since the body releases for a time t = 0 the velocity is zero, therefore the expression remains.
0 = - A w sin Ф
For the equality to be correct, the sine function must be zero, this implies that the phase constant is zero
x = A cos wt
Let's find the point where the kinetic and potential energy are equal.
K = U
½ m v² = m g x
we substitute
½ A² w² sin² wt = g A cos wt
sin² wt = cos wt
let's calculate
w =
w = 5.64 rad / s
sin² 5.64t = 2 9.8 / 0.052 cos 5.64t
sin² 5.64t = 376.92 cos 5.64 t
1 - cos² 5.64t = 376.92 cos 5.64t
cos² 5.64t -376.92 cos564t -1 = 0
we make the change of variable
x = cos 5.64t
x²- 376.92 x - 1 = 0
x = 0.026
cos 5.64t = 0.026
Let's find the displacement for this time
x = 5.2 10-2 0.026
x = 1.35 10-3 m
In conclusion Using the concepts of conservation of energy and harmonic motion we can find the result for the could where the kientic and potential enegies are equal is:
x = 0.135 cm
Learn more here: brainly.com/question/15707891