Answer:
There are 45 turns in the secondary coil.
Explanation:
Given that,
Input potential of the lamp,
The output potential of the lamp,
Number of turns in primary coil,
We need to find the number of turns needed on the secondary coil. We know that the ratio for a transformer is as follows :
So, there are 45 turns in the secondary coil.
Answer:
2m/s²
Explanation:
Given parameters:
Net force on the car = 2000N
Acceleration = 4m/s²
Unknown:
Acceleration of a car twice the mass = ?
Solution:
Let us first find the mass of the car;
Force = mass x acceleration
Mass =
Mass = = 500kg
Now,
whose mass is twice that of the car
Mass of the new car = 2 x 500 = 1000kg
So;
Acceleration =
Acceleration = = 2m/s²
Answer:
The force of friction acting on block B is approximately 26.7N. Note: this result does not match any value from your multiple choice list. Please see comment at the end of this answer.
Explanation:
The acting force F=75N pushes block A into acceleration to the left. Through a kinetic friction force, block B also accelerates to the left, however, the maximum of the friction force (which is unknown) makes block B accelerate by 0.5 m/s^2 slower than the block A, hence appearing it to accelerate with 0.5 m/s^2 to the right relative to the block A.
To solve this problem, start with setting up the net force equations for both block A and B:
where forces acting to the left are positive and those acting to the right are negative. The friction force F_fr in the first equation is due to A acting on B and in the second equation due to B acting on A. They are opposite in direction but have the same magnitude (Newton's third law). We also know that B accelerates 0.5 slower than A:
Now we can solve the system of 3 equations for a_A, a_B and finally for F_fr:
The force of friction acting on block B is approximately 26.7N.
This answer has been verified by multiple people and is correct for the provided values in your question. I recommend double-checking the text of your question for any typos and letting us know in the comments section.