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3 years ago

Four hundred two million seventy-three thousand one hundred eighty in standard form

Mathematics

1 answer:

Makovka662 [10]3 years ago

3 0

402,073,180 = 4.02073180 x 10^8

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dexar [7]

Answer:

Step-by-step explanation:

3x + 5y = 7

Since that is our original form, let's convert it so that we can find the slope:

5y = -3x + 7

y = -3/5 x + y

To get a perpendicular line, we need the negative reciprocal of the slope. This means that the sign switches and numerator and denominator flip:

m = 5/3

From here, we use the point-slope equation and then convert that into slope-intercept form:

y - y1 = m(x - x1)

y - 6 = 5/3(x - 0)

y - 6 = 5/3x

3 0

3 years ago

1. You go to the local Sport Grill for quarter wings day.

DedPeter [7]

Answer:

If the 20% discount is by the hour then the answer would be $11.70 I think.

0.25x78= 19.50

19.50x0.20(20%)= 3.90

19.50-3.90-3.90= 11.70

Hope this helps!

Step-by-step explanation:

8 0

3 years ago

Find the lateral area of the cone in terms of π.

Andreyy89

Answer:

$15\pi\ cm^{2}$

Step-by-step explanation:

we know that

The lateral area of the cone is equal to

$LA=\pi rl$

where

r is the radius of the base

l is the slant height

we have

$r=3\ cm$

Applying the Pythagoras Theorem find the slant height

$l^{2}=3^{2} +4^{2}\\ \\l^{2}=25\\ \\l=5\ cm$

substitute in the formula

$LA=\pi (3)(5)=15\pi\ cm^{2}$

8 0

3 years ago

PQR has vertices at P(-10, 8), Q(0, -6),

nirvana33 [79]

Answer:

please apply the formula of distance

l think but not sure

8 0

2 years ago

Plz help me with this

AnnZ [28]

Answer: $\bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}$

<u>Step-by-step explanation:</u>

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, $B=\dfrac{6}{5}$ → $P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}$

Half of that period is: $\dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}$

Calculate the period for each of the options to find a match:

$A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}$

7 0

3 years ago