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Serjik [45]
3 years ago
10

the set of ordered pairs (–1, 8), (0, 3), (1, –2), and (2, –7) represent a function. what is the range of the function?

Mathematics
2 answers:
Leto [7]3 years ago
8 0
The range of the function is
{-7,2,3,8}.
vodka [1.7K]3 years ago
8 0

Answer:

{y: y = –7, –2, 3, 8}

this would be the answer.

Step-by-step explanation:

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Mrs Smith has 12 times as many markers as color pencils the total number of markers and colored pencils is 78 how many markers d
yawa3891 [41]
<em>x = markers</em>
<em>y = colored pencils</em>

12x = y

x= 72
y = 6

Okay, so what I did was divide 78 by 12 (to find the number of colored pencils) which gave me 6.5. You can't have half a colored pencil, so I rounded the number down to get 6. To find the number of markers, I multiplied 12 and 6 <em>(12x = 6) </em>which gave me 72. To check my answer I added the two amounts, 72 + 6, which gave me 78.

5 0
3 years ago
4^x+7 = 8^2x-3 Solve each equation showing work please
RUDIKE [14]

If 4=2^2

8=2^3

(2^)2x+10=(2^)6x

(2^)6x-(2^)2x=10

(2^)2x×7=10, where x has no real value

3 0
3 years ago
18. Last time Francis checked, her credit score was 659. Since then, she applied
zepelin [54]

Answer:

634

Step-by-step explanation:

659-25=634

Poor little Francis. :(

8 0
3 years ago
An independent-measures research study compares three treatment conditions using a sample of n = 5 in each treatment. For this s
slavikrds [6]

Answer: c. ​10

Step-by-step explanation:

Given : An independent-measures research study compares three treatment conditions using a sample of n = 5 in each treatment.

For this study, the three sample means are, M1 = 1, M2 = 2, and M3 = 3.

Grand mean = \overline{X}=\dfrac{M1+M2+M3}{3} [All sample have equal elements]

=\dfrac{1+2+3}{3}=2

For ANOVA,

SS_{between}=n\sum(M_i-\overline{X})^2 , where i= 1, 2 , 3

SS_{between}=5((1-2)^2+(2-2)^2+((3-2)^2)

SS_{between}=5((-1)^2+(0)^2+((1)^2)= 5(1+1)=10

Hence,the value would be obtained for SS_{between}=10 .

hence, the correct answer = c. ​10

8 0
3 years ago
Plz help, answer the question below
Afina-wow [57]

\sqrt[6]{x^{16}} =\sqrt[6]{x^{12} \cdot x^{4}}=x^2\sqrt[6]{x^{4}}

5 0
3 years ago
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