Four feet are cut from a 12-foot board. What is the percent decrease in length?

A rectangular picture frame measures 18" x 22". If 1 inch equals 2.54 cm, the dimensions of the picture frame in centimeters wou

Kisachek [45]

It would be 45.72 cm by 55.88 cm because you have to multiply each dimension by 2.54 to get the exact measurement in centimeters.

4 0

3 years ago

PLEASE HELP AS SOON AS POSSIBLE

frutty [35]

Answer:

FALSE

TRUE

Step-by-step explanation:

For median,

Arrange your numbers in numerical order.

Count how many numbers you have.

If you have an odd number, divide by 2 and round up to get the position of the median number.

If you have an even number, divide by 2. Go to the number in that position and average it with the number in the next higher position to get the median.

Source: https://www.verywellmind.com/how-to-identify-and-calculate-the-mean-median-or-mode-2795785

So for April median: 2.5, 3, 3.5, 3.5 (since we have 4 numbers we divide by 2 and we count by 2 places from left. Since we have even number data, we average 3 with the next higher position to get the median so (3+3.5)/2 = 3.25

For May apply same concept and you get median to be 2.25.

Median difference is 3.25-2.25 = 1

Therefore, statement 1 is false and statement 2 is true.

For average in May, add all numbers and divide by the number of data points so May= (2.5+3+3.5+3.5)/ 4 = 3.13

Apply same concept you for April and you get 2.38 as mean.

Mean difference is 3.13-2.38 = 0.75

Therefore, statement 3 is correct (true)

4 0

3 years ago

The table below shows the price for different numbers of notebook:

levacccp [35]

So if 2 notebooks cost 12 divide that
12/2 =6 $ each
So to check if its true the 3notebooksx $6 dollars each should =$18 for 3 notebooks
5 notebooks at $6 each = $30 for 5 notebooks
so What is 4notebooks x$6 each ? =4x6 = $24 for 4 notebooks

8 0

3 years ago

What is the distance between nicholas's school and the post office?

aleksklad [387]

Part A:

Given that Nicholas's school is located at point (3, 2) and that the post office is located at point (-2, -2), then the distance between Nicholas's school and the post office is given by:

$d= \sqrt{(-2-3)^2+(-2-2)^2} \\ \\ = \sqrt{(-5)^2+(-4)^2} = \sqrt{25+16} \\ \\ \sqrt{41} =\bold{6.4} \ units$

Part B:

If Nicholas is located at point (– 3 , 2), the distance to get to the grocery store located at point (1,-1) is given by:

$d= \sqrt{(1-(-3))^2+(-1-2)^2} \\ \\ = \sqrt{(1+3)^2+(-3)^2} = \sqrt{(4)^2+9} \\ \\ = \sqrt{16+9} = \sqrt{25} =\bold{5}$

4 0

3 years ago

I NEED HELP PLEASE!!<br> if Q=2.1R+5 find Q when R=5

marusya05 [52]

Answer:

If Q=2.1(R)+5, then it would be 2.1(5)+5=15.5 ?

Step-by-step explanation:

7 0

3 years ago