Given that t<span>here
are 20 light bulbs in 5 packages.
The table to find the rate
that gives you the number of light bulbs in 3 packages is given as follows:
![\begin{tabular} {|c|c|c|c|c|c|} Light bulbs&4&8&12&16&20\\[1ex] Packages&1&2&3&4&5 \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7Cc%7Cc%7Cc%7Cc%7C%7D%0ALight%20bulbs%264%268%2612%2616%2620%5C%5C%5B1ex%5D%0APackages%261%262%263%264%265%0A%5Cend%7Btabular%7D)
Three different ways in which the rate can be written are:
12 light bulbs to 3 packages
12 light bulbs : 3 packages
12 light bulbs / 3 packages
</span>
<h2>First Question:</h2><h3>Given: </h3>
2 km = 1 cm
<h3>To Find:</h3>
The length of the road of 15 km.
<h3>Solution:</h3>
2 km = 1 cm
1 km = 1/2 = 0.5 cm
15 km = 0.5 × 15 = 7.5
<h2>Answer: </h2>
The length of the road is <u>7.5 cm</u>.
Therefore, <u>Option D. 7.5 cm</u> is correct.
Answer:
x = 9 ± √14
Step-by-step explanation:
x² − 18x + 67 = 0
Move the constant to the other side:
x² − 18x = -67
Take half of -18, square it, and add to both sides.
(-18/2)² = (-9)² = 81
x² − 18x + 81 = -67 + 81
x² − 18x + 81 = 14
Factor the perfect square:
(x − 9)² = 14
Solve for x:
x − 9 = ±√14
x = 9 ± √14
Answer:
June 17
Step-by-step explanation:
the least common multiple of 4 and 6 is 12. Add 12 to June 5 and you get June 17
Answer:
radius=6
Step-by-step explanation: