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Sindrei [870]
3 years ago
8

Need help pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeWhat is (f⋅g)(x)?

Mathematics
1 answer:
Sergio039 [100]3 years ago
5 0

just need to multiply and axpand ?

( {x}^{2}  + 2)( {x}^{3}  - 4x + 2) =  {x}^{2} ({x}^{3}  - 4x + 2) + 2({x}^{3}  - 4x + 2) \\  =  {x}^{5}  - 4 {x}^{3}  + 2 {x}^{2}  + 2 {x}^{3}  - 8x + 4 \\  =  {x}^{5}  - 2 {x}^{3}  + 2 {x}^{2}  - 8x + 4

You might be interested in
est the hypothesis using the​ P-value approach. Be sure to verify the requirements of the test. Upper H 0 : p equals 0.89 versus
hichkok12 [17]

Answer:

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the population proportion significantly differs from 0.89.

The requirements for the test are satisfief.

n(1-p)=70>10

Step-by-step explanation:

This is a hypothesis test for a proportion.

There are 3 requirements to have a valid test of proportion: random sample, independence and normal.

For the first two (random and independent sample) we don't have details, but we assume the sampling has been random.

The latter can be verified by calculating np and n(1-p):

np=430>10\\\\n(1-p)=70>10

Both are bigger than 10, so the normal approximation can be considered appropiate.

The claim is that the population proportion significantly differs from 0.89.

Then, the null and alternative hypothesis are:

H_0: \pi=0.89\\\\H_a:\pi\neq 0.89

The significance level is 0.01.

The sample has a size n=500.

The sample proportion is p=0.86.

p=X/n=430/500=0.86

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.89*0.11}{500}}\\\\\\ \sigma_p=\sqrt{0.000196}=0.014

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.86-0.89+0.5/500}{0.014}=\dfrac{-0.029}{0.014}=-2.072

This test is a two-tailed test, so the P-value for this test is calculated as:

\text{P-value}=2\cdot P(z

As the P-value (0.038) is greater than the significance level (0.01), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the population proportion significantly differs from 0.89.

6 0
3 years ago
I really need Help with this equation Please!!!!
Slav-nsk [51]

Answer:

Option D:  - 6;  $ \textbf{-5}\frac{\textbf{5}}{\textbf{2}} $;   $ \textbf{-4}\frac{\textbf{1}}{\textbf{5}} $.

Step-by-step explanation:

The sequence is defined by:

$ A(n) = -6 + (n - 1)\bigg( \frac{1}{5} \bigg ) $

To find the first term of the sequence simply substitute n = 1.

First term of the sequence:

$ A(1) = -6 + (1 - 1)\bigg( \frac{1}{5} \bigg ) $

        $ = - 6 $

Fourth term of the sequence:

$ A(2) = -6 + (4 - 1) \bigg ( \frac{1}{5} \bigg) $

        $ = - 6 + 3\bigg( \frac{1}{5} \bigg) $

        $ = \frac{- 30 + 3}{5} $

        $ = \frac{-27}{5} $

        $ = \frac{-25 - 2}{5} $

        $ = - 5 - \frac{2}{5} $

        $ = -5\frac{2}{5} $   is the required answer.

Tenth term of the sequence:

$ A(10) = - 6 + (10 - 1) \bigg( \frac{1}{5} \bigg) $

         $ = - 6 + 9\bigg( \frac{1}{5} \bigg) $

         $ = \frac{-30 + 9}{5} $

         $ = \frac{-21}{5} $

         $ = \frac{-20 - 1}{5} $

         $ = - 4 - \frac{1}{5} $

         $ = -4\frac{1}{5} $  is the required answer.

       

       

3 0
4 years ago
A population of flies grows according to the function p(x) = 3(2)x, where x is measured in weeks. A local spider has set up shop
kifflom [539]
The answer is 14 flies 

1. Calculate the population of flies after 3 weeks without the spider: p(3)
2. Calculate the number of eaten flies by the spider after 3 weeks: s(3)
3. Subtract p(3) and s(3) to get  the population of flies after three weeks with the introduced spider.

1. Calculate the population of flies after 3 weeks without the spider:
     p(x) = 3(2)ˣ
     x = 3 (because it is the period of three weeks)
⇒  p(3) = 3 · 2³ = 3 · 8
     p(3) = 24

2. Calculate the number of eaten flies by the spider after 3 weeks:
      s(x) = 2x + 4
      x = 3 (because it is the period of three weeks)
⇒   s(3) = 2 · 3 + 4 = 6 + 4
      s(3) = 10

3. Subtract p(3) and s(3) to get  the population of flies after three weeks with the introduced spider:
    p(3) - s(3) = 24 - 10 = 14
Therefore, there are 14 flies after three weeks with the introduced spider.
6 0
4 years ago
What is 3/4 to the negative 1 power
umka21 [38]

Answer:

4/3

Step-by-step explanation:

To the power of negative one just means 1 divided by and 1 divided by 3/4 is just 4/3

3 0
3 years ago
barb exercises for 22 hours each week. how many hours does she exercise in 14 weeks. use the array drawn on the grid go help mul
PSYCHO15rus [73]

Answer:

308 hours

Step-by-step explanation:

22 x 13

8 0
3 years ago
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