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Marat540 [252]
3 years ago
15

In which sample is the average kinetic energy of the particles greatest?

Chemistry
2 answers:
Over [174]3 years ago
8 0
The question asks about the average kinetic energy, so it is related only to temperature. Then the answer is (3) with the highest temperature.
Stels [109]3 years ago
3 0

Answer: The correct answer is option 3.

Explanation: Average kinetic energy is defined as the energy of motion of the particles of a system. It is a measure of Kelvin Temperature.

Mathematically,

K=\frac{3}{2}\frac{R}{N_A}T

where,

K = kinetic energy of the molecules measured in joules.

R = Gas constant = 8.314Jmol^{-1}K^{-1}

N_A = Avogadro's number = 6.022\times 10^{23}atoms/mol

T = Temperature in kelvins.

Kinetic energy is directly proportional to the temperature of the system.

\text{Kinetic energy}\propto \text{Temperature}

More the temperature, more will be the kinetic energy of the molecules.

Hence, the correct answer is Option 3.

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3 years ago
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What are the observable properties of salt and rocks, and explain how you used empirical evidence to explain that mixtures of so
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Answer:

Appearance. Pure rock salt is colorless. However, when found underground it is generally not completely pure, so may have yellow, red, gray or brown hues. It is either transparent or translucent and when you shine a light on it, its luster is vitreous, meaning it appears shiny and glassy.

Explanation:

6 0
3 years ago
Is this an aromatic hydrocarbon? Why or why not?
swat32
The correct answer is D

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Determine the volume in mL of 0.37 M HClO4(aq) needed to reach the half-equivalence (stoichiometric) point in the titration of 2
Dimas [21]

Answer:

14.3mL you require to reach the half-equivalence point

Explanation:

A strong acid as HClO₄ reacts with a weak base as CH₃CH₂NH₂, thus:

CH₃CH₂NH₂ + HClO₄ → CH₃CH₂NH₃⁺ + ClO₄⁻

As the reaction is 1:1, to reach the equivalence point you require to add the moles of HClO₄ equal to moles CH₃CH₂NH₂ you add originally. Also, half-equivalence point requires to add half-moles of CH₃CH₂NH₂ you add originally.

Initial moles of CH₃CH₂NH₂ are:

20.8mL = 0.0208L × (0.51mol CH₃CH₂NH₂ / 1L) =

0.0106moles CH₃CH₂NH₂

To reach the half-equivalence point you require:

0.0106moles ÷ 2 = 0.005304 moles HClO₄

As concentration of HClO₄ is 0.37M, volume you require to add 0.005304moles is:

0.005304 moles HClO₄ ₓ (1L / 0.37mol) = 0.0143L =

<h3> 14.3mL you require to reach the half-equivalence point</h3>

7 0
3 years ago
Mr. Holmes and Mrs. Nogaki are having a good old fashioned Baby Back Ribs BBQ contest and are arguing over who’s BBQ produces le
ExtremeBDS [4]

Answer:

Mrs. Nogaki is right because Mr. Holmes’s BBQ produces 3x more CO2 for each mole of fuel burned.

Explanation:

Now Mrs. Nogaki has already figured out the chemical combustion reaction behind the operation of her BBQ. It is pertinent to reproduce it here.

CH4(g) + 2O2(g)→CO2(g) +2H2O(g)

She already has this figured out but Mr. Holmes doesn't have any chemical reaction equation to back his claims. Let us help him with the correct combustion equation for propane.

C3H8(g) + 5O2(g) + 3CO2(g) + 4H2O(g)

We can clearly see from the reaction equation that Mr. Holmes BBQ produces three times more carbon IV oxide than Mr. Nogaki's BBQ so Mr. Nogaki was right in her claim after all.

Hence the answer!

5 0
3 years ago
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