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2 years ago

In which sample is the average kinetic energy of the particles greatest?

2 answers:

8 0

The question asks about the average kinetic energy, so it is related only to temperature. Then the answer is (3) with the highest temperature.

Stels [109]2 years ago

3 0

Answer: The correct answer is option 3.

Explanation: Average kinetic energy is defined as the energy of motion of the particles of a system. It is a measure of Kelvin Temperature.

Mathematically,

$K=\frac{3}{2}\frac{R}{N_A}T$

where,

K = kinetic energy of the molecules measured in joules.

R = Gas constant = $8.314Jmol^{-1}K^{-1}$

$N_A$ = Avogadro's number = $6.022\times 10^{23}atoms/mol$

T = Temperature in kelvins.

Kinetic energy is directly proportional to the temperature of the system.

$\text{Kinetic energy}\propto \text{Temperature}$

More the temperature, more will be the kinetic energy of the molecules.

Hence, the correct answer is Option 3.

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3 years ago

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kolezko [41]

We have to get the relationship between metallic character and atomic radius.

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3 years ago

Which of the following statements is true about an endergonic reaction? ∆G is positive ∆G is negative ∆S is negative

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3 years ago

The chemical formula of ordinary sugar is C12H22O11. Calculate the mass of 7.35 mol of sugar.

ch4aika [34]

First, you need to find the mass of 1 mol of sugar. Mass, or molar mass, can simply be found by adding the masses of the individual elements. These are given to you on the periodic table.

$C_{12}H_{22}O_{11}$

12 x 12.011 grams (molar mass of Carbon) = 144.132 g

22 x 1.008 grams (molar mass of Hydrogen) = 22.176 g

11 x 15.999 grams (molar mass of Oxygen) = 175.989 g

Add all of the pieces together.

144.132 g + 22.176 g + 175.989 g = 342.297 grams

So, if one mole has 342.297 grams, then 7.35 of that amount will be your answer.

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3 years ago

Difference between qualitative and quantitative data in chemistry

const2013 [10]

Quantitative data is numerical.
Qualitative data is non-numerical.
Hope this helps.
have a great day.

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3 years ago