<h3><u>Full Question:</u></h3>
The following compound has been found effective in treating pain and inflammation (J. Med. Chem. 2007, 4222). Which sequence correctly ranks each carbonyl group in order of increasing reactivity toward nucleophilic addition?
A) 1 < 2 < 3
B) 2 < 3 < 1
C) 3 < 1 < 2
D) 1 < 3 < 2
<h3><u>Answer: </u></h3>
The rate of nucleophilic attack of carbonyl compounds is 2<3 <1.
Option B
<h3><u>Explanation. </u></h3>
Nucleophilic attack is explained as the attack of an electron rich radical to a carbonyl compound like aldehyde or a ketone. A nucleophile has a high electron density, so it searches for a electropositive atom where it can donate a portion of its electron density and become stable.
A carbonyl compound is a
hybridized carbon atom with a double bonded oxygen atom in it. The oxygen atom pulls a huge portion of electron density from carbon being very electropositive.
In a ketone, there are two factors that make it less likely to undergo a nucleophilic attack than aldehyde. Firstly, the steric hindrance of two carbon groups being attached with the carbonyl carbon makes it harder for the nucleophile to approach. Secondly, the electron push by the carbon groups attached makes the carbonyl carbon a bit less electropositive than the aldehyde one. So aldehydes are more reactive towards a nucleophilic addition reaction.
Answer:
4 a minor but very important component of the atmosphere corban dioxide is released through natural processes such as reputation.;
Explanation:
a minor but very important component of the atmosphere corban dioxide is released through natural processes such as reputation
4 3 and 5 are wrong:)
4 is true and 5 is false
4. insulators are really thick materials that keep electrons within their space.
For example, a charger the rubber is the insulators and the electrons are flowing inside of the charger so you don't get shocked.
5. without the force of attraction, there are no atoms:)
for number 3, its a trick question
Hope this helped!
(learned these this year so I didn't forget them:)
I have provided the steps to figure out the number of atoms in the chemical compound.