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Temka [501]
3 years ago
10

In order for Sean to earn a B in his Algebra 1 course, his test scores must average at least 80%. On the

Mathematics
1 answer:
inn [45]3 years ago
6 0
Assuming that the exam weight is 100, you would need at least an 80 on the test
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The force needed to stop a car varies directly as its weight W and the square root of velocity V are inversely as the distance d
svet-max [94.6K]

Answer:

Step-by-step explanation:

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2 years ago
What are the x and y-intercepts of the line described by the equation?<br><br> 3x−9y=10.8
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3x-9y=10.8\\\\x-intercept\ for\ y=0:\\\\3x-9(0)=10.8\\\\3x-0=10.8\\\\3x=10.8\qquad\text{divide both sides by 3}\\\\\boxed{x=3.6\to(3.6,\ 0)}\\\\y-intercept\ for\ x=0:\\\\3(0)-9y=10.8\\\\0-9y=10.8\\\\-9y=10.8\qquad\text{divide both sides by (-9)}\\\\\boxed{y=-1.2\to(0,\ -1.2)}

3 0
3 years ago
What is a formula for the nth term of a given sequence
IceJOKER [234]

Answer:

a_n=-12-4(n-1)

Step-by-step explanation:

The given sequence is

-12,-16,-20...

The first term of this sequence is a_1=-12.

The common difference is

d=-16--12

d=-16+12=-4

The nth term of this arithmetic sequence is;

a_n=a_1+d(n-1)

We substitute the values for the first term and the common difference to obtain;

a_n=-12-4(n-1)

5 0
2 years ago
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How do I find the Area of a Cylinder
Mandarinka [93]

Answer:

A=2πrh+2πr^2

Step-by-step explanation:

6 0
2 years ago
What is the distance between the points (21 , 13) and (3 , 13) in the coordinate plane?
Oxana [17]

Answer:

\displaystyle d = 18

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point (21, 13)

Point (3, 13)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formula]:                                                         \displaystyle d = \sqrt{(3-21)^2+(13-13)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                   \displaystyle d = \sqrt{(-18)^2+(0)^2}
  3. [√Radical] Evaluate exponents:                                                                       \displaystyle d = \sqrt{324+0}
  4. [√Radical] Add:                                                                                                 \displaystyle d = \sqrt{324}
  5. [√Radical] Evaluate:                                                                                          \displaystyle d = 18
5 0
3 years ago
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