Using the quadratic equation instead of calculus, you can find the x coordinate of the vertex as it will be the midpoint of the two x coordinates of the zeros...
x=(-3±√-27)/2
x=-1.5±√-6.75
That the second term is imaginary does not matter because we will add or subtract this value from -1.5, thus the midpoint of the zeros, the x coordinate of the vertex is -1.5. And to find the value of y for the vertex we just find the value of y when x=-1.5
y(-1.5)=6.75
Since y>0, the vertex is above the x-axis.
The sum of the function will be (r – s)(x) = –2x² + x – 3, The difference of the function will be (r – s)(x) = –2x² + x – 3, and The product of the function will be (r × s)(x) = 2x³ – 6x².
The complete question is attached below.
<h3>What is Algebra?</h3>
The analysis of mathematical representations is algebra, and the handling of those symbols is logic.
The functions are given below.
r(x) = x – 3
s(x) = 2x²
The sum of the function will be
(r + s)(x) = x – 3 + 2x²
(r + s)(x) = 2x² + x – 3
The difference of the function will be
(r – s)(x) = (x – 3) – 2x²
(r – s)(x) = –2x² + x – 3
The product of the function will be
(r × s)(x) = (x – 3) (2x²)
(r × s)(x) = 2x³ – 6x²
More about the Algebra link is given below.
brainly.com/question/953809
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Let t, h, b represent the weighs of tail, head, and body, respectively.
t = 4 . . . . given
h = t + b/2 . . . . the head weighs as much as the tail and half the body
b/2 = h + t . . . . half the body weighs as much as the head and tail
_____
Substituting for b/2 in the second equation using the expression in the third equation, we have
... h = t + (h + t)
Subtracting h from both sides gives
... 0 = 2t . . . . . . in contradiction to the initial statement about tail weight.
Conclusion: there's no solution to the problem given here.
Answer:
is a function that reverse another function if de function apply to an input x gives a result of a y den applying its inverse function g to y gives de result of x nd opposite eg f (x )=y nd if g (y )=x